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Propel和I18N:如果没有找到,则回退到另一个区域设置

[英]Propel and I18N: fallback to another locale if first is not found

I am currently working on a API allowing users to get some event messages on their devices. 我目前正在开发一个API,允许用户在他们的设备上获取一些事件消息。 Users call my API specifying me their preferred locale (for instance fr_FR ). 用户调用我的API为我指定他们的首选语言环境(例如fr_FR )。

On the back-office, administrators can choose the languages they want to support. 在后台,管理员可以选择他们想要支持的语言。 Let's assume they choose English and Chinese. 我们假设他们选择英语和中文。 So, they do not support French language. 所以,他们不支持法语。

I am using the Propel I18N behavior to deal with all the translations. 我正在使用Propel I18N行为来处理所有翻译。 In my requests, I am currently doing: 在我的要求中,我目前正在做:

SystemMessageQuery::create()
    ->joinWithI18N('fr_FR')
    ->findOne();

It works correctly if I specify an existing locale. 如果我指定现有的语言环境,它可以正常工作。 Yet, if the translation is not available, it returns null. 但是,如果翻译不可用,则返回null。 Sounds logical. 听起来合乎逻辑。

My question is: can I fallback the user on a default locale (in this case, en_US ) if the provided locale is not planned by an administrator? 我的问题是:如果管理员没有计划提供的语言环境,我可以使用默认语言环境(在本例中为en_US )回退用户吗? If yes, how can I proceed? 如果是,我该怎么办?

I thought to send a prior request to check if the locale exists. 我想发送一个先前的请求来检查语言环境是否存在。 But I do not think it is a good way for performances reasons (especially for an API). 但我不认为这是出于性能原因(特别是API)的好方法。

Any idea? 任何想法?

According to the documentation , there is not such a fallback in Propel. 根据文档 ,Propel没有这样的后备。

What you can try, is the combination of setLocale and joinWithI18N . 您可以尝试的是setLocalejoinWithI18N的组合。 Something like: 就像是:

$default_locale = 'en_US';
$items = ItemQuery::create()
  ->joinWithI18n('fr_FR')
  ->find();

foreach ($items as $item) 
{
  echo $item->getPrice();

  // test if name is translated
  if (!$name = $item->getName())
  {
    // otherwise, try to get the translation with default locale
    $item->setLocale($default_locale);
    $name = $item->getName(); // one query to retrieve the English translation
  }
}

I haven't tested this code but it seems to be a solution. 我没有测试过这段代码,但它似乎是一个解决方案。

Also, have you tried to add two joinWithI18N (one for en_US & one for fr_FR ) to see how the query handle it? 此外,您是否尝试添加两个joinWithI18N (一个用于en_US和一个用于fr_FR )以查看查询如何处理它?

Finally, I used the following code: 最后,我使用了以下代码:

public function setLocale($locale = 'en_US', $fallbackEnabled = false)
{
    if($fallbackEnabled) {

        $localeExists = SystemMessageI18nQuery::create()
            ->filterByLocale($locale)
            ->filterById($this->getId())
            ->count();

        if(!$localeExists) {
            $locale = SystemMessageI18nQuery::create()
                ->filterById($this->getId())
                ->select('locale')
                ->findOne();
        }

    }

    parent::setLocale($locale);
}

It is not the best solution for performance reasons, but it is functionnal. 它不是出于性能原因的最佳解决方案,但它是功能性的。

Try something like this 尝试这样的事情

public function joinWithI18nFallback($locale=null, $joinType = Criteria::LEFT_JOIN, $default_locale=null)
{

    $languages = sfConfig::get('sf_languages');
    if(null == $locale)
    {
        $locale = sfPropel::getDefaultCulture();
    }

    if(null == $default_locale)
    {
        $default_locale = sfPropel::getDefaultCulture();
    }

    $languages[] = $locale;
    $languages[] = $default_locale;
    $languages   = array_unique($languages);

        $FallbackQuery = CategoryQuery::create()
                                                  ->leftJoin('CategoryI18n')
                                                  ->addJoinCondition('CategoryI18n', "CategoryI18n.Culture IN ('".implode("','", $languages)."')" )
                                                  ->withColumn('CategoryI18n.Culture', 'CultureDefault')
                                                  ->addAscendingOrderByColumn("FIELD(category_i18n.culture, '".$locale."', '".implode("','", $languages)."' )")
                                                  ->where("CategoryI18n.name != ''");

         $this->addSelectQuery($FallbackQuery, 'Category')
              ->join('CategoryI18n', $joinType)
              ->addJoinCondition('CategoryI18n', 'CategoryI18n.Culture = Category.CultureDefault' )
              ->with('CategoryI18n')
              ->groupById();

     $this->with['CategoryI18n']->setIsWithOneToMany(false);

    return $this;
}

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