尝试将行与正则表达式匹配

Question

I am trying to match the following line:

801. Our origination charge (Includes Originat ion Point (s) %  or $ ) (f rom GFE #1)$ 1,169.00

I have created this regular expression:

.*801\\..*\\(f\\s?rom.*$\\s?(.*)

What this should do is:

1. Match anything up until 801.
2. Match anything until(f\\s?rom
3. Match anything until $
4. Optional space
5. Match the rest of line line

The way I believe this breaks my string down is like so:

1. 801.
2. Our origination charge (Includes Originat ion Point (s) % or $ )
3. (f rom GRE #1
4. (nothing)
5. 1,169.00

However this is not the case. My regular expression does not match this string. Any ideas why?

Answer 1

Escape your dollar sign $ . It's the end-of-line anchor .

.*801\..*\(f\s?rom.*\$\s?(.*)

Answer 2

.*801\..*\(f\s?rom.*\$\s?.*

Escape the $ character. And remove the brackets in the end.This regex exactly matches the string.