Java正则表达式：没有哈希的href

Question

I'm trying to build a sitemap and parsing the html bodies for href s that doesn't have # (as those with hashes are just sub chapter links in some content page htmls).

My regexp now: <a\\\\s[^>]*href\\\\s*=\\\\s*\\"([^\\"]*)\\"[^>]*>(.*?)</a> I guess I should use [^#] or !# to exclude the # from href s but could not solve it with just trying and googling after it. Thanks in advance for helping me out!

Answer 1

Done it. Just inserted the # too in the [^\\"] block. :D

<a\\s[^>]*href\\s*=\\s*\"([^\"#]*)\"[^>]*>(.*?)</a>

Answer 2

You should not use regex to parse HTML.

Best use an HTML parser, as eg http://jsoup.org and then

Document doc = Jsoup.parse(input);
Elements links = doc.select("a[href]");

for (Element each: links) {
    if (each.attr("href").startsWith("#")) continue;
    ...
}

So much more painless than using regex, eh!