需要有关PHP $ _FILE文件上载脚本的帮助

Question

I am creating an upload script with PHP and HTML that could have any number of file uploads. I loop through and echo out any number of file uploads and name each one "fileField1", "fileField2" and so on using a loop.

Now I want to retrieve the name of the file in that field. Can I use a variable in another loop like this?

  $fileField = 'fileField'.$i;

    $fileName = $_FILES[$fileField]['name']; // Name of file 

This is contained within the loop, will this work?

I believe I am experiencing an error...

Variable $i is increased by one each time ($i++)

EDIT

Notice the comment that I never reach...

Here is the whole loop:

$i = 1;
while ($i <= $numberOfFields) {
$fileField = 'fileField'.$i;
$titleId = 'title'.$i;
$genreId = 'genre'.$i;

    $fileName = $_FILES[$fileField]['name']; // Name of file 

    if($fileName !=""){
        $randNum = rand(1000000000,9999999999); //Generate random number

        $newFileName = $fileName."-".$randNum; //Rename file

            if (file_exists($baseUrl."images/".$newFileName)){
            echo $newFileName." already exists. ";
            }else{      
                if(isset($_POST[$titleId]) && !empty($_POST[$titleId])){
                    // Assign url, title, genre
                    $url = 'images/'.$newFileName;          
                    $title = $_POST[$titleId];          
                    $genre = $_POST[$genreId]; 
                    // Execute final query and upload
                    $sql = "INSERT INTO images (url,title,genre) VALUES (:url,:title,:genre)";
                    $q = $conn->prepare($sql);
                    $q->execute(array(':url'=>$url,
                                      ':title'=>$title,
                                      ':genre'=>$genre));       
                    if(copy($_FILES['fileField']['tmp_name'],'../images/'.$newFileName)) {
                        $NOTICE = 'File successfully uploaded!';
                        // I AM NEVER REACHING THIS NOTICE WHICH IS ECHOED LATER ON IN THE CODE
                    }
                }else{
                    $NOTICE = "Please fill out the title for picture ".$i;
                    break;                  
                }
            }
    }else{
        $NOTICE = "Please select a file to upload in slot ".$i;
        break;
    }
    $i++;
    }

Answer 1

if(copy($_FILES['fileField']['tmp_name'],'../images/'.$newFileName)) {

I believe should be:

if(move_uploaded_file($_FILES['fileField']['tmp_name'],'../images/'.$newFileName)) {

And yes, you can put variables in [] like that. So long as they're valid and won't result in an undefined offset error.

Answer 2

Don't use copy . Use move_uploaded_file first, before you do anything with the uploaded file. Files are uploaded to a special, temporary location.