从文件读取到列表并让每个元素都通过该程序

Question

Sorry if the title is confusing. What I want to do is have a text file (keywords.txt) read and then split into a list. So basically lets say the file contained "iphone, keys, wallet, pen, folder", I would want the list to be [iphone, keys, wallet, pen, folder].

Is there any way to set one variable to work for each element. Say the variable is query. Is there anyway for query to be each of the elements so it can go through the program and work for each element. Below is the code I have, it obviously doesnt work but that is what I want to happen if possible.

The reason I want to do it for each is because eventually the script will write a new text file for each of the elements and name it based on what the element is and the only way I know how to do that is by having one variable.

data = [line.strip() for line in open('keywords.txt', 'r')]

try:
    query = sys.argv[1]
except IndexError:
    query = item in data 

Here is the rest of the code that I will be performing. It will take what is in the list that is created and create a new textfile and a csv file.

newFile = open("%s.txt" %query, 'w').write(txt.encode('utf8'))

with open("%s.txt" %query, 'rb') as input_file:
    reader = csv.reader(input_file, delimiter='\n', quoting = csv.QUOTE_NONE)

    with open("%s.csv" %query, 'wb') as output_file:
        writer = csv.writer(output_file)

        for row in reader:
            writer.writerow(row)

Answer 1

Turn the query value taken from the command line into a list instead, then loop over the query list:

try:
    query = [sys.argv[1]]
except IndexError:
    query = data

for q in query:
    # do something with q

Answer 2

def process_keywords_in_file(file_name):  
    with open(file_name) as f:
        for line in f:
            process(line.strip())

def process(keyword):
    #your code

if you want to write a new file with the name of the keyword:

with open('%s.txt' % keyword, 'w') as fw:
    fw.write('content')