将文件读入列表并从每个列表元素中删除换行符

Question

Im trying to read a text file contents into a list and then strip the newline from list element. however, i am receiving the incorrect output.

infile = open('kennedy.txt','r')
line1 = infile.readline()
line2 = infile.readline() 
line3 = infile.readline() 
line4 = infile.readline() 
line5 = infile.readline() 
line6 = infile.readline() 

strip

line1 = line1.rstrip('\n')
line2 = line2.rstrip('\n')
line3 = line3.rstrip('\n')
line4 = line4.rstrip('\n')
line5 = line5.rstrip('\n')
line6 = line6.rstrip('\n')

My expected output is:

We observe today not a victory
of party but a celebration
of freedom symbolizing an end
as well as a beginning
signifying renewal as well
as change

False
Error reading the file: no_kennedy.txt

[Errno 2] No such file or directory: 'no_kennedy.txt'
True

but my actual output is:

false

false

ive been reviewing my notes still dont know why its not giving me the proper output.

Answer 1

Typically, to read the content of a file you can as follows.

SEPARATOR = "\n"

with open('kennedy.txt','r') as f:
    content = [line.strip() for line in f]

Reading line-by-line as you did is not advisable, given that generally you don't know how many lines a files as

With this, you have a list with all the lines already stripped from trailing/leading spaces. The you can decide if you want output them line by line:

for line in content:
    print(line)

or join in a monolitic text, using a separator, for example

joined_content = SEPARATOR.join(content)
print(joined_content)

VERY IMPORTANT : in any case, your file is kennedy.txt , not no_kennedy.txt - which one exists in your directory?

Answer 2

First, make sure you use the same file. In the code, you used 'kennedy.txt', but the error is throwing 'no_kennedy.txt'.

Try this, and see.

with open('kennedy.txt','r', encoding='utf-8') as infile:
for line in infile.readlines():
    print(line.replace(r"\n", ""))