搜索结束用Java在xml中排除

Question

I'm trying to search these occurrences in xml file: 我正在尝试在xml文件中搜索这些事件：

<xml>  
<corpus>  
<body>  
<nonterminals>  
<graph>  
<s>  
<nt id="s9_509" cat="fcl"></nt>  

<nt id="s9_501" cat="pp">  
                <edge label="H" idref="s9_1"/>  
                <edge label="DP" idref="s9_502"/>  
                <edge label="STA" idref="s9_509"/>  
                <edge label="P" idref="s9_19"/>  
                <edge label="S" idref="s9_510"/>  
                <edge label="PU" idref="s9_25"/>  
            </nt>  
</nonterminals>  
</graph>  
</s>  
</body>  
</corpus>  
</xml>

And my code is: 我的代码是：

XPath xpath = XPathFactory.newInstance().newXPath();    
String path = "//xml//corpus//build//s//graph//nonterminals//nt";  
XPathExpression expr = xpath.compile(path);    
System.out.println("Query1: "+path);  
Object result = expr.evaluate(document, XPathConstants.NODESET);    
NodeList nodes = (NodeList) result;    
System.out.println("Number of nodes: "+nodes.getLength());  
for (int i = 0; i < nodes.getLength(); i++) {    
    System.out.println(nodes.item(i).getAttributes().getNamedItem("id").getNodeValue());

This query its correct? 这个查询正确吗？ Exists another way to try it? 存在另一种尝试方法吗？ How do I delete the Node findings? 如何删除节点结果？

Answer 1

Providing that this is the entire structure of your XML and <xml> is your root node, I would say that your XPath should be: 假设这是XML的整个结构，而<xml>是您的根节点，那么我想说您的XPath应该是：

/xml/corpus/build/s/graph/nonterminals/nt

If you want to match every nt node regardless of where it appears in the document, you could use: 如果要匹配每个 nt节点而不管它在文档中出现的位置如何，可以使用：

//nt

There are useful free tools for seeing the results of XPath queries without needing to write java upfront: 有一些有用的免费工具，无需查看Java就可以查看XPath查询的结果：

http://xml-copy-editor.sourceforge.net/ http://xml-copy-editor.sourceforge.net/

http://www.xpathtester.com/ http://www.xpathtester.com/

搜索结束用Java在xml中排除

问题描述

1 个解决方案

解决方案1
0 2012-12-11 17:33:25

搜索结束用Java在xml中排除

问题描述

1 个解决方案

解决方案1 0 2012-12-11 17:33:25

解决方案1
0 2012-12-11 17:33:25