搜索結束用Java在xml中排除

Question

我正在嘗試在xml文件中搜索這些事件：

<xml>  
<corpus>  
<body>  
<nonterminals>  
<graph>  
<s>  
<nt id="s9_509" cat="fcl"></nt>  

<nt id="s9_501" cat="pp">  
                <edge label="H" idref="s9_1"/>  
                <edge label="DP" idref="s9_502"/>  
                <edge label="STA" idref="s9_509"/>  
                <edge label="P" idref="s9_19"/>  
                <edge label="S" idref="s9_510"/>  
                <edge label="PU" idref="s9_25"/>  
            </nt>  
</nonterminals>  
</graph>  
</s>  
</body>  
</corpus>  
</xml>

我的代碼是：

XPath xpath = XPathFactory.newInstance().newXPath();    
String path = "//xml//corpus//build//s//graph//nonterminals//nt";  
XPathExpression expr = xpath.compile(path);    
System.out.println("Query1: "+path);  
Object result = expr.evaluate(document, XPathConstants.NODESET);    
NodeList nodes = (NodeList) result;    
System.out.println("Number of nodes: "+nodes.getLength());  
for (int i = 0; i < nodes.getLength(); i++) {    
    System.out.println(nodes.item(i).getAttributes().getNamedItem("id").getNodeValue());

這個查詢正確嗎？ 存在另一種嘗試方法嗎？ 如何刪除節點結果？

Answer 1

假設這是XML的整個結構，而<xml>是您的根節點，那么我想說您的XPath應該是：

/xml/corpus/build/s/graph/nonterminals/nt

如果要匹配每個 nt節點而不管它在文檔中出現的位置如何，可以使用：

//nt

有一些有用的免費工具，無需查看Java就可以查看XPath查詢的結果：

http://xml-copy-editor.sourceforge.net/

http://www.xpathtester.com/

搜索結束用Java在xml中排除

問題描述

1 個解決方案

解決方案1
0 2012-12-11 17:33:25

搜索結束用Java在xml中排除

問題描述

1 個解決方案

解決方案1 0 2012-12-11 17:33:25

解決方案1
0 2012-12-11 17:33:25