[英]How to store templated heterogeneous objects in an STL container
The question is about a code developed in MS Visual C++ 11, with access only to STL, no Boost. 问题是关于在MS Visual C ++ 11中开发的代码,只能访问STL,没有Boost。
There is a wrapper template class, roughly with this header: 有一个包装器模板类,大致有这个标头:
template <typename Payload>
class Wrapper {
Payload p;
std::string src;
Wrapper( std::string, Payload );
Payload get(); // returns payload
void set(Payload); // replaces payload
void operator ()(); // uses payload
}
Payload
may be anything - pointer, int, even heavy object. Payload
可能是任何东西 - 指针,整数,甚至是重物。
Later, Wrapper
s need to go in a container, like std::vector
- but regardless of their specific parameter type. 后来,
Wrapper
需要进入一个容器,比如std::vector
- 但不管它们的具体参数类型如何。 And that gives me trouble because container needs homogeneous elements. 这给我带来了麻烦,因为容器需要同质的元素。
I have tried the base class suggestions like this from KennyTM , however it gives me some issues with methods get()
and set()
- those need cast (?) when used from a vector because elements look like a base class if used in the pattern suggested by that answer. 我已经尝试过KennyTM这样的基类建议,但是它给了我一些方法
get()
和set()
- 当从向量中使用时需要强制转换 (?)因为元素看起来像一个基类,如果在该答案提出的模式。
For that you will need to use some sort of type erasure. 为此,您需要使用某种类型的擦除。 From the most basic (provide a base type, store the elements by pointer to the base) to fancier solutions like boost::any you get to choose (I know you mentioned no boost, but you can always take a look at the implementation).
从最基本的(提供基本类型,通过指针存储元素到基础)到更高级的解决方案,如boost ::任何你可以选择(我知道你提到没有提升,但你总是可以看看实现) 。 Alternatively you could use a variant approach (similar to boost::variant) if the set of payloads is known and relatively small, but that might be harder to implement for a single use.
或者,如果有效载荷集是已知的并且相对较小,则可以使用变体方法(类似于boost :: variant),但是对于单次使用可能更难实现。
template<typename Payload>
struct Wrapper;
struct WrapperBase {
std::string src;
WrapperBase( std::string s ):src(s) {}
template<typename Payload>
Payload get() const;
template<typename Payload>
void set(Payload);
virtual void operator ()() = 0; // uses payload
};
template <typename Payload>
struct Wrapper {
Payload payload;
Wrapper( std::string s, Payload p ):WrapperBase(s),payload(p) {}
Payload get() const { return payload; }; // returns payload
void set(Payload p) { payload = p; }; // replaces payload
virtual void operator()() override; // todo
}
template<typename Payload>
Payload WrapperBase::get() const {
Assert(dynamic_cast<Wrapper<Payload> const*>(this));
return static_cast<Wrapper<Payload> const*>(this)->get();
}
template<typename Payload>
void WrapperBase::set(Payload p) {
Assert(dynamic_cast<Wrapper<Payload>*>(this));
static_cast<Wrapper<Payload>*>(this)->set(p);
}
Users of a WrapperBase
, if they want to set/get the payload, need to know what the type of the payload is. 如果
WrapperBase
用户想要设置/获取有效负载,则需要知道有效负载的类型。 You can use dynamic_cast<Wrapper<Payload>*>
to figure out if a given WrapperBase
is a specific kind if you don't know. 如果您不知道,可以使用
dynamic_cast<Wrapper<Payload>*>
来确定给定的WrapperBase
是否是特定类型。
This doesn't have value semantics, so you'll want to store a vector
of smart pointers to WrapperBase
rather than actual instances. 这没有值语义,因此您需要将智能指针的
vector
存储到WrapperBase
而不是实际实例。 std::shared_ptr
or std::unique_ptr
are good candidates with very different behavior. std::shared_ptr
或std::unique_ptr
是具有非常不同行为的好候选者。
If there is a finite bounded set of Payloads
, a visitor pattern can work. 如果存在有限的
Payloads
集,则访问者模式可以起作用。
If you need value semantics, a pImpl
pattern that stores the actual payload can do that with manual operator=
that clones the pImpl
. 如果您需要值语义,那么存储实际有效负载的
pImpl
模式可以使用手动operator=
来克隆pImpl
。
Asking "do you hold type T
" is possible, but generally is similar to a dynamic_cast
. 询问“你持有
T
型”是可能的,但通常类似于dynamic_cast
。
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