[英]Get response from the web service for HttpResponse
In my application, the User can upload images to a PHP server, the iOS version is working 100%, the Android version used for this tutorial to upload image: tutorial example 在我的应用程序中,用户可以将图像上载到PHP服务器,iOS版本可正常工作100%,本教程所使用的Android版本用于上载图像: 教程示例
And the function I'm using is this: 我正在使用的功能是这样的:
public static String sendPost(String url, String imagePath)
throws IOException, ClientProtocolException {
HttpClient httpclient = new DefaultHttpClient();
httpclient.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,
HttpVersion.HTTP_1_1);
HttpPost httppost = new HttpPost(url);
File file = new File(imagePath);
MultipartEntity mpEntity = new MultipartEntity();
ContentBody cbFile = new FileBody(file, "image/jpeg");
mpEntity.addPart("userfile", cbFile);
httppost.setEntity(mpEntity);
//Log.e("executing request " + httppost.getRequestLine());
HttpResponse response = httpclient.execute(httppost);
HttpEntity resEntity = response.getEntity();
//Log.e(""+response.getStatusLine());
if (resEntity != null) {
//Log.e(EntityUtils.toString(resEntity));
}
if (resEntity != null) {
resEntity.consumeContent();
}
httpclient.getConnectionManager().shutdown();
return response.toString();
}
return response.toString(); 返回response.toString(); get it in org.apache.http.message.BasicHttpResponse @ 406dc148 在org.apache.http.message.BasicHttpResponse @ 406dc148中获取它
But the return of the web service is the URL where the image was saved, I need to have a string in the return of the PHP server, rather than the return I mentioned above how can I have it? 但是Web服务的返回是保存图像的URL,我需要在PHP服务器的返回中包含一个字符串,而不是上面提到的返回如何拥有它?
I wanted something like this (HttpURLConnection): HttpURLConnection conn; 我想要这样的东西(HttpURLConnection):HttpURLConnection conn; ... ...
String response= "";
Scanner inStream = new Scanner(conn.getInputStream());
while(inStream.hasNextLine())
response+=(inStream.nextLine());
Log.e("resp", response);
After one hour onsegui trying to get the response from the Web service as follows: ... 一小时后,onsegui试图从Web服务获取响应,如下所示:...
byte [] responseBody = httppost.getMethod().getBytes();
Log.e("RESPONSE BODY",""+(new String(responseBody)));
... ...
If you want the content returned by the HTTP server, you shouldn't do this: 如果要HTTP服务器返回的内容,则不应执行以下操作:
if (resEntity != null) {
resEntity.consumeContent();
}
... because that says "throw away the content". ...因为它说“扔掉内容”。
Try this if the response is of type String 如果响应的类型为String,请尝试此操作
ResponseHandler<String> responseHandler = new BasicResponseHandler();
HttpResponse httpResponse = httpClient.execute(post, new BasicHttpContext()); // new BasicHttpContext() not necessary
// verify connection response status using httpResponse.getStatusLine().getStatusCode() then
String response = responseHandler.handleResponse(httpResponse);
if(response != mull){
Log.e("Response : "+response);
}else{
// Handle exception
}
return response;
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