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從Web服務獲取對HttpResponse的響應

[英]Get response from the web service for HttpResponse

在我的應用程序中,用戶可以將圖像上載到PHP服務器,iOS版本可正常工作100%,本教程所使用的Android版本用於上載圖像: 教程示例

我正在使用的功能是這樣的:

public static String sendPost(String url, String imagePath) 
        throws IOException, ClientProtocolException  {
    HttpClient httpclient = new DefaultHttpClient();
    httpclient.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION,
                                        HttpVersion.HTTP_1_1);

    HttpPost httppost = new HttpPost(url);
    File file = new File(imagePath);

    MultipartEntity mpEntity = new MultipartEntity();
    ContentBody cbFile = new FileBody(file, "image/jpeg");
    mpEntity.addPart("userfile", cbFile);

    httppost.setEntity(mpEntity);
    //Log.e("executing request " + httppost.getRequestLine());
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity resEntity = response.getEntity();

    //Log.e(""+response.getStatusLine());
    if (resEntity != null) {
        //Log.e(EntityUtils.toString(resEntity));
    }
    if (resEntity != null) {
        resEntity.consumeContent();
    }
    httpclient.getConnectionManager().shutdown();
    return response.toString();

}

返回response.toString(); 在org.apache.http.message.BasicHttpResponse @ 406dc148中獲取它

但是Web服務的返回是保存圖像的URL,我需要在PHP服務器的返回中包含一個字符串,而不是上面提到的返回如何擁有它?

我想要這樣的東西(HttpURLConnection):HttpURLConnection conn; ...

String response= "";
Scanner inStream = new Scanner(conn.getInputStream());

while(inStream.hasNextLine())
    response+=(inStream.nextLine());
Log.e("resp", response);

一小時后,onsegui試圖從Web服務獲取響應,如下所示:...

byte [] responseBody = httppost.getMethod().getBytes(); 
Log.e("RESPONSE BODY",""+(new String(responseBody)));

...

如果要HTTP服務器返回的內容,則不應執行以下操作:

if (resEntity != null) {
    resEntity.consumeContent();
}

...因為它說“扔掉內容”。

如果響應的類型為String,請嘗試此操作

  ResponseHandler<String> responseHandler = new BasicResponseHandler();
  HttpResponse httpResponse = httpClient.execute(post, new BasicHttpContext()); // new BasicHttpContext() not necessary 
// verify connection response status using httpResponse.getStatusLine().getStatusCode() then

  String response =  responseHandler.handleResponse(httpResponse);
  if(response != mull){
     Log.e("Response : "+response);
  }else{
   // Handle exception 
  }
 return response;

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