尝试将矩阵1 * 3转换为列表

Question

I am currently getting:

y=[[ 0.16666667]
[-0.16666667]
[ 0.16666667]]

This comes out of a function im using and i need to turn the above into a list in the format below:

x= [0.16666667,-0.16666667,0.16666667]

I tried list(y) but this does not work, because it returns:

[array([ 0.16666667]), array([-0.16666667]), array([ 0.16666667])]

How exactly would I do this??

Answer 1

my_list = [col for row in matrix for col in row]

Answer 2

You can use the numpy .tolist() method:

array.tolist()

There is also one more advantage to it... It works with matrix objects, the list comprehension doesn't. If you want to remove the dimension first you can use numpy methods to do so, such as array.squeeze()

Answer 3

使用列表推导从每个子列表中获取第一个元素：

x = [elt[0] for elt in y]