[英]Seg Fault Looping over C++ containers
Here's the code(find union of 2 sets) : 这是代码(查找2套并集):
template <class dtype>
void printSet(dtype data)
{
std::cout<<"\n";
for(auto i = data.begin(); i != data.end(); i++)
{
std::cout<<*i<<" ,";
}
}
int main(int argc, char const *argv[])
{
int arr[] = {1,2,3,4,5};
std::set<long long> a(arr, arr + 5), b(arr, arr + 5), c;
std::vector<long long> v;
b.insert(1000);
printSet(a);
printSet(b);
set_union(a.begin(), a.end(), b.begin(), b.end(), v.begin());
printSet(v);
return 0;
}
And here's what I got: 这就是我得到的:
1 ,2 ,3 ,4 ,5 ,
[1] 9444 segmentation fault ./a.out
Where did I mess up ? 我在哪里弄糟?
v
is empty, so writing to v.begin()
isn't possible. v
为空,因此无法写入v.begin()
。 You should use std::back_inserter(v)
instead. 您应该改用
std::back_inserter(v)
。
set_union
expects a valid output iterator, in the sense that it should be allowed to write at that iterator. 在应该允许
set_union
写入该迭代器的意义上, set_union
期望有效的输出迭代器。 v
is empty, so v.begin()
isn't a valid iterator. v
是空的,因此v.begin()
不是有效的迭代器。
Try declaring your vector as 尝试将向量声明为
std::vector<long long> v(42);
For clarity: if you flush std::cout
before the set_union
line, you should see that b
was printed as well. 为了清楚起见:如果在
set_union
行之前刷新std::cout
,则应该看到b
也已打印。
As to the error, I suggest adding this include: 对于错误,我建议添加以下内容:
#include <iterator>
and changing your set_union
line to: 并将您的
set_union
行更改为:
set_union(a.begin(), a.end(), b.begin(), b.end(), back_inserter(v));
The back_insert_iterator
returned by back_inserter
is an output iterator suitable for use here: it will call v.push_back
for each item assigned to it by set_union
. back_insert_iterator
返回的back_inserter
是适合在此使用的输出迭代器:它将为v.push_back
为其分配的每个项目调用set_union
。
In general, you should make sure your core file size limit is non-zero (just make it unlimited unless you're writing massive programs), and learn to examine the core file with your debugger. 通常,您应确保核心文件大小限制为非零(除非编写大型程序,否则请使其不受限制),并学会使用调试器检查核心文件。
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