如何从现有RegEx模式中排除一些单词

Question

I have the following pattern that matches placeholders such as ( %s , %16.6fAl , %d , etc.):

%([az]+)\\b|%([a-z0-9\\.]{2,20})\\b

I do, however, need to ignore the following placeholders:

%w %1w %2w %3w %O %M

I've tried to look up and check the forum, but I'm afraid my regex knowledge is limited. Is there anyone out there that may have a solution?

Answer 1

If you want to match all placeholders except five very specific ones, and your code allows it, the easiest way is probably to first match all the placeholders, then (if matched) use another regexp to check for the five "prohibited" ones and ignore them. Writing a RegExp that will match %d , %1d , %4d , %4w but will not match %1w will be... interesting. Certainly possible, just not fun.

Answer 2

Your might try this one. It fulfills your given examples.

%([a-lnp-vx-z]+)\\b|%((?:[0-9][^w]{1,19})|(([az.]{2,20})))\\b

Answer 3

I think you may want to pattern match what you actually want instead of trying exclude what you don't want.

Here is a rough regexp for printf

%([+- #0])?(([1-9][0-9]*)|\*)?(\.([1-9][0-9]*)|\*)?([hljztL]|hh|ll)?[diuoxXfFeEgGaAspn]