[英]CUFFT with double precision
I am experiencing some problems with CUDAs FFT library. 我在使用CUDA FFT库时遇到一些问题。
I declared the inputs as cuDoubleComplex, but the compiler returns the error that this type is incompatible with parameters of type cufftComplex. 我将输入声明为cuDoubleComplex,但是编译器返回以下错误:此类型与cufftComplex类型的参数不兼容。 After some search through the Internet, I found the file cufft.h, in which there is the line
typedef cuComplex cufftComplex;
通过Internet进行搜索后,我找到文件cufft.h,其中包含
typedef cuComplex cufftComplex;
. 。 My problem is that in the library cuComplex.h it is clear that cuComplex has a single floating point precision (
typedef cuFloatComplex cuComplex;
), but I would like a double precision. 我的问题是,在cuComplex.h库中,很显然cuComplex具有单浮点精度(
typedef cuFloatComplex cuComplex;
),但是我想要双精度。
Is this possible? 这可能吗?
In particular, I obtain the following: 特别是,我获得以下信息:
error: argument of type "cufftDoubleComplex *" is incompatible with parameter of type "cufftComplex *"
at this line: 在这一行:
cufftExecC2C(plan, data1, data2, CUFFT_FORWARD);
The double precision complex data type is defined as cufftDoubleComplex
in CUFFT. 双精度复杂数据类型在CUFFT中定义为
cufftDoubleComplex
。
Double precision versions of fft in CUFFT are: CUFFT中fft的双精度版本是:
cufftExecD2Z() //Real To Complex
cufftExecZ2D() //Complex To Real
cufftExecZ2Z() //Complex To Complex
cufftExecC2C
is the single precision version of fft, and expects the input and output pointers to be of type cufftComplex
,whereas you are passing it a pointer of type cufftDoubleComplex
. cufftExecC2C
是fft的单精度版本,并且期望输入和输出指针的类型为cufftComplex
,而您要cufftComplex
传递的类型为cufftDoubleComplex
的指针。
For cufftDoubleComplex
data type, you have to use the function cufftExecZ2Z
instead, which is for double precision data. 对于
cufftDoubleComplex
数据类型,必须改为使用函数cufftExecZ2Z
,该函数用于双精度数据。
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