使用 wsprintf 将 int 转换为 wchar_t*

Question

I'm trying to get a wchar_t* formatted with an int as a parameter. I've Googled a lot but I've only ended up more confused. So, consider this code:

int main(int argc, char** argv) {

   wchar_t buf[16];
   wsprintf(buf, L"%d", 5);
   wprintf(L"[%ls]\n", buf);

   system("pause");
   return 0;

};

Having assumed that wchar_t , wsprintf and wprintf are the wide character equivalents of char , sprintf and printf respectively, I expected the above to print [5] , but it prints garbage between [ and ] . What is the correct way to achieve the desired result? And what am I misunderstanding here?

(I should clarify that portability is more important than security here, so I'd like to know a solution that uses this family of functions instead of safer vendor-specific extensions.)

Answer 1

wsprintf() is a Windows-specific function, it's unavailable on Unixes. What you want to achieve can be done in a more portable way (I have tried this slightly modified code snippet and it worked as expected):

#include <wchar.h>
#include <stdio.h>

int main(int argc, char **argv)
{
    wchar_t buf[16];
    swprintf(buf, sizeof(buf) / sizeof(*buf), L"%d", 5);
    wprintf(L"[%ls]\n", buf);

    return 0;
}

Output:

[5]

Answer 2

wsprintf() is one of Microsoft's hybrid functions. It has a different signature depending on whether or not _UNICODE is defined during preprocessing. (What's happening under the hood, is there's an #ifdef that replaces wsprintf with wsprintfA or wsprintfW based on the nonexistence or existence of that symbol.)

If _UNICODE is defined, it expects the buffer to be of wchar_t[] .

If _UNICODE is not defined (usually the default), it expects the buffer to be char[] . That's what's happening here. If you had warnings on, it would probably show a warning about incompatible pointer types. The garbage is because the 8-bit ascii that it's storing in buf is being interpreted as Unicode by wprintf() .

Answer 3

It appears to me that you're using an incorrect format specifier for your output. I would suspect you would want

wprintf(L"[%s]\n", buf);

%ls looks like an invalid combination of specifiers - l for a "long int" size prefix on the s "string" type specifier. Documentation I've found on wprintf indicates that it treats the 's' type specifier as pointing to a wide character string (at least for MS Visual Studio).