PHP preg_match正则表达式捕获字符串中的模式

Question

I can't seem to get Regular Expressions right whenever I need to use them ...

Given a string like this one:

$string = 'text here [download="PDC" type="A"] and the text continues [download="PDS" type="B"] and more text yet again, more shotcodes might exist ...';

I need to print the "text here" part, then execute a mysql query based on the variables "PDC" and "A", then print the rest of the string... (repeating all again if more [download] exist in the string).

So far I have the following regex

$regex = '/(.*?)[download="(.*?)" type="(.*?)"](.*?)/';
preg_match($regex,$string,$res);
print_r($res);

But this is only capturing the following:

Array ( [0] => 111111 [1] => 111111 [2] => ) 

I'm using preg_match() ... should I use preg_match_all() instead? Anyway ... the regex is surely wrong... any help ?

Answer 1

[ opens character class, and ] finishes it. Such characters with meaning need to be either escaped or put into a QE block in PCRE regex.

/(.*?)\Q[download="\E(.*?)" type="(.*?)"](.*?)/
      ##^          ##         ^-- you were looking for "tipo"
        |
  this character needs to be taken literal, hence the \Q....\E around it
                                                      ##    ##

Answer 2

Try it with with "little" one

/(?P<before>(?:(?!\\[download="[^"]*" type="[^"]*"\\]).)*)\\[download="(?P<download>[^"]*)" type="(?P<type>[^"]*)"\\](?P<after>(?:(?!\\[download="[^"]*" type="[^"]*"\\]).)*)/

It will provide you the keys before , after , download and type in the matches result.

Test it here: http://www.regex101.com/r/mF2vN5