如何在C语言中将char *添加到char **

Question

I have an array of char arrays in C (not C++). The type is char**. I know it's length, but the lengths of the elements are unknown. and I have another char* array. Need to append this char* to my char**, as the last element.

Answer 1

How about:

char **pointers;
char *p;
/* ... */
pointers[last] = p;

The one thing you need to get right is the value of last and you can easily keep track of it as you add elements to pointers .

EDIT

A simple way to keep track of last is to always say:

pointers[last++] = p;

Another way is to keep a copy and advance it:

char **pts = pointers;
/* .. */
pts = p;
pts++;

Answer 2

char* arr1[]; //known length with some already filled elements

each element of the above array is a pointer to character array.

char *new = "lastElem" // this is the string you have to append

let us say, arr1 has n elements(each a string). Then,

arr1[++n] = new; // this should do it, provided space exists in arr1 and you already have the //character array 'new'.

Answer 3

Quite easy with realloc :

char **array = ...;
array = realloc(array, sizeof(char*)*(LENGTH+1));
array[LENGTH] = last;

(I'm assuming you need to increase the size of array , otherwise array[LENGTH-1] = last is enough)