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java:如何使用bufferedreader读取特定的行

[英]java: how to use bufferedreader to read specific line

Lets say I have a text file called: data.txt (contains 2000 lines) 假设我有一个名为的文本文件:data.txt(包含2000行)

How do I read given specific line from: 500-1500 and then 1500-2000 and display the output of specific line? 如何读取给定的特定行:500-1500然后1500-2000并显示特定行的输出?

this code will read whole files (2000 line) 此代码将读取整个文件(2000行)

public static String getContents(File aFile) {

        StringBuffer contents = new StringBuffer();

        try {

        BufferedReader input = new BufferedReader(new FileReader(aFile));
        try {
            String line = null; 

            while (( line = input.readLine()) != null){
            contents.append(line);
            contents.append(System.getProperty("line.separator"));
            }
        }
        finally {
            input.close();
        }
        }
            catch (IOException ex){
            ex.printStackTrace();
        }

        return contents.toString();
}

How do I modify above code to read specific line? 如何修改上面的代码以读取特定的行?

I suggest java.io.LineNumberReader. 我建议使用java.io.LineNumberReader。 It extends BufferedReader and you can use its LineNumberReader.getLineNumber(); 它扩展了BufferedReader,你可以使用它的LineNumberReader.getLineNumber(); to get the current line number 获取当前行号

You can also use Java 7 java.nio.file.Files.readAllLines which returns a List<String> if it suits you better 您还可以使用Java 7 java.nio.file.Files.readAllLines返回List<String>如果它更适合您)

Note: 注意:

1) favour StringBuilder over StringBuffer, StringBuffer is just a legacy class 1)在StringBuffer上使用StringBuilder,StringBuffer只是一个遗留类

2) contents.append(System.getProperty("line.separator")) does not look nice use contents.append(File.separator) instead 2) contents.append(System.getProperty("line.separator"))看起来不太好使用contents.append(File.separator)代替

3) Catching exception seems irrelevant, I would also suggest to change your code as 3)捕获异常似乎无关紧要,我还建议将代码更改为

public static String getContents(File aFile) throws IOException {
    BufferedReader rdr = new BufferedReader(new FileReader("aFile"));
    try {
        StringBuilder sb = new StringBuilder();
        // read your lines
        return sb.toString();
    } finally {
        rdr.close();
    }
}

now code looks cleaner in my view. 现在代码看起来更干净了。 And if you are in Java 7 use try-with-resources 如果您使用Java 7,请使用try-with-resources

    try (BufferedReader rdr = new BufferedReader(new FileReader("aFile"))) {
        StringBuilder sb = new StringBuilder();
        // read your lines
        return sb.toString();
    }

so finally your code could look like 所以最后你的代码看起来像

public static String[] getContents(File aFile) throws IOException {
    try (LineNumberReader rdr = new LineNumberReader(new FileReader(aFile))) {
        StringBuilder sb1 = new StringBuilder();
        StringBuilder sb2 = new StringBuilder();
        for (String line = null; (line = rdr.readLine()) != null;) {
            if (rdr.getLineNumber() >= 1500) {
                sb2.append(line).append(File.pathSeparatorChar);
            } else if (rdr.getLineNumber() > 500) {
                sb1.append(line).append(File.pathSeparatorChar);
            }
        }
        return new String[] { sb1.toString(), sb2.toString() };
    }
}

Note that it returns 2 strings 500-1499 and 1500-2000 请注意,它返回2个字符串500-1499和1500-2000

A slightly more cleaner solution would be to use FileUtils in apache commons. 更简洁的解决方案是在apache commons中使用FileUtils。 http://commons.apache.org/io/api-release/org/apache/commons/io/FileUtils.html Example snippet: http://commons.apache.org/io/api-release/org/apache/commons/io/FileUtils.html示例代码段:

String line = FileUtils.readLines(aFile).get(lineNumber);

The better way is to use BufferedReader. 更好的方法是使用BufferedReader。 If you want to read line 32 for example: 如果您想阅读第32行,例如:

for(int x = 0; x < 32; x++){
    buf.readLine();
}
lineThreeTwo = buf.readLine();

Now in String lineThreeTwo you have stored line 32. 现在在String lineThreeTwo中你存储了第32行。

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