如果表中没有结果显示X，则PHP MySQL

Question

I have a query on my site and if there is no results, I'd like to say something else rather than have a blank page...

    $sth = $conn->prepare("SELECT * FROM directory WHERE user_active != '' AND County = :county");
    $sth->execute(array(':county' => $county));

    $c = 1;
    while ($row = $sth->fetch(PDO::FETCH_ASSOC)) {
        RETURNED DATA GOES HERE
    $c++;
    }

Answer 1

$sth->execute(array(':county' => $county));
if ($sth->rowCount() == 0) {
   echo 'no rows';
} else {
   while(yada yada yada) { ... }
}

Relevant docs: http://php.net/manual/en/pdostatement.rowcount.php

Answer 2

You're counting the results in $c , so you can check which value that has by appending your code with this:

if($c == 1) { // Counter is stuck at 1
    echo "No results were found.";
}

Answer 3

2种可能的解决方案，执行SELECT COUNT执行fetchall检查并稍后显示结果