[英]If no results in table show X, PHP MySQL
我在我的网站上有一个查询,如果没有结果,我想说些别的,而不是空白页...
$sth = $conn->prepare("SELECT * FROM directory WHERE user_active != '' AND County = :county");
$sth->execute(array(':county' => $county));
$c = 1;
while ($row = $sth->fetch(PDO::FETCH_ASSOC)) {
RETURNED DATA GOES HERE
$c++;
}
$sth->execute(array(':county' => $county));
if ($sth->rowCount() == 0) {
echo 'no rows';
} else {
while(yada yada yada) { ... }
}
您要在$c
计算结果,因此可以通过在代码后附加以下内容来检查具有哪个值:
if($c == 1) { // Counter is stuck at 1
echo "No results were found.";
}
2种可能的解决方案,执行SELECT COUNT执行fetchall检查并稍后显示结果
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