缓慢的php / mysql结果-显示加载图像？

Question

I have a website that is running php/MySQL to query and return results. The result set is over 40,000 and the query is getting slower. I want to find a simple way to display a loading image while the page builds. I can do it with any page running JavaScript but I assume since php is server side I need to handle the loading differently.

I see that AJAX has a load() function where I can call the php page and presumable show a loading image while the request is loading. Is that the best way? I can't believe that there aren't lots of example scripts floating around since this has to be a very common problem.

Answer 1

Are you using an AJAX request to do this? If so, it's as simple as using JavaScript to display an image when you send the request, then hide it again upon success/error. You can just keep an <img> tag around with "display: none" and turn it on/off as needed.

If you aren't using AJAX, then this will be impossible, as the page does not exist until the query is completed.

On a side note: it's incorrect to say that "AJAX has a load() function". AJAX is not a code base or a library, it is a technique. Perhaps you mean jQuery.ajax, or some other library?

Answer 2

您必须使用Ajax，我估计使用PHP和AJAX将数据从表单加载到MySQL中将非常有用，并遵循jQuery API以获得Ajax参考