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确保在StringTemplate中转义HTML实体的最佳方法是什么

[英]What is the best way to ensure HTML entities are escaped in StringTemplate

Assuming the following string template, is being given a list of Java Bean objects: 假设下面的字符串模板,将被提供Java Bean对象的列表:

<ul>$people:{p|<li>$p.name$ $p.email</li>}$</ul>

ie the list of people might contain Person objects which you may or may not have the ability to enhance/extend: 即人员列表可能包含您可能无法增强/扩展的Person对象:

class Person {
    ....
    public getName() { ... }
    public getEmail() { ... }
}

The getName() and getEmail() methods don't return sanitised (escaped html entities). getName()getEmail()方法不会返回经过清理的(转义的html实体)。 How do you get around this? 您如何解决这个问题?

You may use a custom renderer, for example: 您可以使用自定义渲染器,例如:

public static class HtmlEscapeStringRenderer implements AttributeRenderer {
    public String toString(Object o, String s, Locale locale) {
        return (String) (s == null ? o : StringEscapeUtils.escapeHtml((String) o));
    }
}

Then in the template indicate you want it escaped: 然后在模板中指示您希望其转义:

$p.name;format="html"$

That said, you may prefer to scrub the data on input, convert before sending to the template, send a decorated person to the template, etc. 也就是说,您可能更喜欢清理输入的数据,在发送到模板之前进行转换,将经过装饰的人发送到模板等。


public class App {
    public static void main(String[] args) {
        STGroupDir group = new STGroupDir("src/main/resource", '$', '$');
        group.registerRenderer(String.class, new HtmlEscapeStringRenderer());

        ST st = group.getInstanceOf("people");
        st.add("people", Arrays.asList(
                new Person("<b>Dave</b>", "dave@ohai.com"),
                new Person("<b>Nick</b>", "nick@kthxbai.com")
        ));

        System.out.println(st.render());
    }

    public static class HtmlEscapeStringRenderer implements AttributeRenderer {
        public String toString(Object o, String s, Locale locale) {
            return (String) (s == null ? o : StringEscapeUtils.escapeHtml((String) o));
        }
    }
}

This outputs: 输出:

<ul><li>&lt;b&gt;Dave&lt;/b&gt; dave@ohai.com</li><li>&lt;b&gt;Nick&lt;/b&gt; nick@kthxbai.com</li></ul>

It's not necessary to write your own renderer for this. 无需为此编写自己的渲染器。 You may use the builtin renderer org.stringtemplate.v4.StringRenderer 您可以使用内置渲染器org.stringtemplate.v4.StringRenderer

group.registerRenderer(String.class, new StringRenderer());

and add in your template : 并添加您的模板:

<ul>$people:{p|<li>$p.name;format="xml-encode"$ $p.email;format="xml-encode"$</li>}$</ul>

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