[英]Java method for type safe return generic subclass
I'm using the following code to get the first matching element with the given class (Dog, Cat) from a list of abstract type (Animal). 我正在使用以下代码从抽象类型(Animal)列表中获取具有给定类(Dog,Cat)的第一个匹配元素。 Is there another type safe way to do it?
还有其他类型的安全方法吗?
// get the first matching animal from a list
public <T extends Animal>T get(Class<T> type) {
// get the animals somehow
List<Animal> animals = getList();
for(Animal animal : animals) {
if(type.isInstance(animal)) {
// this casting is safe
return (T)animal;
}
}
// if not found
return null;
}
// both Cat and Dog extends Animal
public void test() {
Dog dog = get(Dog.class); // ok
Cat cat = get(Dog.class); // ok, expected compiler error
}
(Cat and Dog extends Animal) (猫与狗延伸动物)
The code looks correct. 代码看起来正确。 This line:
这一行:
Cat cat = get(Dog.class);
Indeed should not compile. 确实不应该编译。
I would make sure you're not using rawtypes anywhere in your code, as often this will "opt out" of generics for seemingly unrelated code. 我会确保你没有在你的代码中的任何地方使用rawtypes,因为这通常会“选择”出现看似无关的代码的泛型。
I get compiler error with your code: 我的代码出现编译器错误:
public void test() {
Dog dog = get(Dog.class); // ok
Cat cat = get(Dog.class); // compiler error
}
and I can see only one case when it may compile: 我只能看到一个可编译的案例:
class Dog extends Cat {
}
I would change one thing in your code. 我会在你的代码中改变一件事。 Instead of
代替
return (T)animal;
I would use 我会用
return type.cast(animal);
The latter will not generate unchecked cast warning. 后者不会生成未经检查的投射警告。
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