[英]Parsing Array in PHP based on Key Values
Basic php question here. 基本的PHP问题在这里。 The following SQL code returns an array containing a key called 'date'. 以下SQL代码返回一个包含名为'date'的键的数组。 All I want to do is parse the 'date' value based on the key name. 我要做的就是根据键名解析“ date”值。 Any help? 有什么帮助吗?
$result = mysql_query("SELECT * FROM `table` WHERE columnName ='value'") or die(mysql_error());
$data = array();
while ( $row = mysql_fetch_assoc($result) )
{
$data[] = $row;
}
echo $data->{'date'}
Ok here you go 好,你去
With Foreach 与Foreach
foreach($data as $key => $value)
{
if($key == 'date')
{
// do you parsing stuff
}
}
Without foreach 没有foreach
$parsing_date = $data['date'];
您在无法使用的数组上使用对象语法。
echo $data['date'],
foreach($data as $key => $value)
{
if ($key == 'date')
{
echo "Date Value: '".$value."'";
// Do your stuffs...
echo "Date Final Value: '".$value."'";
}
}
mysql_fetch_assoc returns an ASSOCiative array. mysql_fetch_assoc返回一个ASSOCiative数组。 Which means it returns an array with your table name fields as keys. 这意味着它将返回一个以您的表名字段为键的数组。 For example if your table has 3 columns 'date', 'name', and 'color' 例如,如果您的表有3列“日期”,“名称”和“颜色”
Then you would access those fields in the following way. 然后,您可以通过以下方式访问这些字段。
$result = mysql_query("SELECT * FROM `table` WHERE columnName ='value'") or die(mysql_error());
$data = array();
while ( $row = mysql_fetch_assoc($result) )
{
echo $row['date']; //Prints the rows date field
echo $row['name']; //Prints the row name field and so on.
}
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