[英]How to declare of array of pointers to 2D arrays
I have a list of 2D arrays: 我有一个二维数组的列表:
float a[][9] = { ... }
float b[][9] = { ... }
float c[][9] = { ... }
I want to have another array of pointers that point to each of the 2D arrays, like this: 我想要另一个指向每个2D数组的指针数组,如下所示:
what_should_be_here?? arr[] = { a, b, c }
How to achieve this? 如何实现呢?
Use typedef
to simplify declaration. 使用
typedef
简化声明。 Each of the element of arr is float (*)[9]
. arr的每个元素都是
float (*)[9]
。 Say this type is SomeType
. 说这种类型是
SomeType
。 Then {a,b,c}
means you need an array of three elements of type SomeType
. 然后
{a,b,c}
表示您需要一个由SomeType
类型的三个元素组成的SomeType
。
SomeType arr[] = {a,b,c};
Now the question is, what is SomeType
? 现在的问题是,
SomeType
是什么 ? So here you go: 因此,您在这里:
typedef float (*SomeType)[9]; //SomeType is a typedef of `float (*)[9]`
SomeType arr[] = {a,b,c}; //this will compile fine now!
As I said, use typedef
to simplify declaration! 如我所说, 使用
typedef
简化声明!
I would choose a better name for SomeType
: 我会为
SomeType
选择一个更好的名称:
typedef float (*PointerToArrayOf9Float)[9];
PointerToArrayOf9Float arr[] = {a,b,c};
That is a longer name, but then it makes the code readable! 这是一个较长的名称,但随后使代码可读!
Note that without typedef, your code will look like this: 请注意,没有typedef,您的代码将如下所示:
float (*arr[])[9] = {a,b,c};
which is UGLY. 这很丑。 That is why I will repeat:
这就是为什么我会重复:
typedef
to simplify declaration! typedef
简化声明! Hope that helps. 希望能有所帮助。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.