[英]Converting Dynamic ArrayList to Json
I want to convert an array list to json string of a specific format. 我想将数组列表转换为特定格式的json字符串。 I get all the users emails in an array list and want to convert it into the following format of JSON. 我将所有用户电子邮件发送到数组列表中,并希望将其转换为以下JSON格式。
[
{"email":"abc@gmail.com"},
{"email":"xyz@gmail.com"}
]
My controller action is 我的控制器动作是
public static Result apiCustomers(){
List<Customer> customerList = Model.coll(Customer.class).find().toArray();
List<String> emails = new ArrayList<String>();
for(Customer c : customerList){
emails.add(c.email);
}
//ObjectNode result = Json.newObject();
//result.put("emails", Json.toJson(emails));
return ok();
}
How can I convert the emails list to the above json format? 如何将电子邮件列表转换为上述json格式?
Thanks in advance 提前致谢
Why use another JSON ser/des lib? 为什么要使用另一个JSON ser / des lib? Play has one built-in (a wrapper around jackson - which is really fast). Play内置了一个(杰克逊周围的包装器-速度非常快)。
Starting from your code: 从您的代码开始:
public static Result apiCustomers(){
List<Customer> customerList = Model.coll(Customer.class).find().toArray();
List<String> emails = new ArrayList<String>();
for(Customer c : customerList){
emails.add(c.email);
}
return ok(Json.toJson(emails));
}
This uses some defaults but should be enough. 这使用一些默认值,但应该足够了。
Or manually: 或手动:
public static Result apiCustomers(){
ArrayNode arrayNode = new ArrayNode(JsonNodeFactory.instance);
List<Customer> customerList = Model.coll(Customer.class).find().toArray();
for(Customer c : customerList){
ObjectNode mail = Json.newObject();
mail.put("email", c.email);
arrayNode.add(mail);
}
return ok(arrayNode);
}
No need for Gson. 不需要Gson。
You can use this library: http://code.google.com/p/google-gson/ 您可以使用以下库: http : //code.google.com/p/google-gson/
Pretty easy tutorial about it here: http://www.mkyong.com/java/how-do-convert-java-object-to-from-json-format-gson-api/ 关于此的非常简单的教程: http : //www.mkyong.com/java/how-do-convert-java-object-to-from-json-format-gson-api/
Or you can write a custom toJson method to your classes or an util Json (not a big deal) 或者,您可以将自定义的toJson方法写入您的类或util Json(没什么大不了的)
in your case it should be something like that (i didn't test it): 在你的情况下应该是这样的(我没有测试):
public String toJson(List<String> emails) {
StringBuilder result = new StringBuilder();
result.append("[");
result.append("\n");
for (String s : emails) {
result.append("{");
result.append("\"email\":");
result.append("\"");
result.append(s);
result.append("\"");
result.append("}");
result.append(",");
result.append("\n");
}
result.append("]");
return result.toString();
}
With the benefit of Java 8 (and I suspect a newer Jackson version): 受益于Java 8(我怀疑是Jackson的较新版本):
private static final ObjectMapper mapper = new ObjectMapper();
...
List<Customer> customerList = Model.coll(Customer.class).find().toArray();
ArrayNode emails = mapper.createArrayNode();
customerList.forEach(c -> emails.add(c.email));
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.