[英]How to open a program from a text file in Python
How would I go about opening a file in Python by referring to a text file. 如何通过引用文本文件在Python中打开文件。 EXAMPLE:
例:
f.open('openthis.txt')
Then I would have openthis.txt in the same folder that would say: 然后,我将在同一文件夹中显示openthis.txt:
C:\\Folder\\myprogram.exe
C:\\ Folder \\ myprogram.exe
Therefore the code opens up myprogram.exe from the directory 因此,该代码从目录打开了myprogram.exe。
I want to do this so the code is easily changable, instead of having to edit it in IDLE every time I want to change the file I open. 我想这样做是为了使代码易于更改,而不是每次我要更改打开的文件时都必须在IDLE中对其进行编辑。
You want the subprocess module. 您需要子流程模块。 Specifically, you'd do something like:
具体来说,您可以执行以下操作:
import subprocess
with open("inputfile", "rb") as f:
subprocess.call(f.read())
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