How to open a program from a text file in Python

Question

How would I go about opening a file in Python by referring to a text file. EXAMPLE:

    f.open('openthis.txt')

Then I would have openthis.txt in the same folder that would say:

C:\\Folder\\myprogram.exe

Therefore the code opens up myprogram.exe from the directory

I want to do this so the code is easily changable, instead of having to edit it in IDLE every time I want to change the file I open.

Answer 1

You want the subprocess module. Specifically, you'd do something like:

import subprocess

with open("inputfile", "rb") as f:
    subprocess.call(f.read())