[英]Windows Forms PictureBox - how to display the image in a certain area of the form
I'm using the following code to open and display image in one of my forms using fileDialog
: 我正在使用以下代码使用
fileDialog
在我的一个表单中打开和显示图像:
private void btnExplorer_Click(object sender, EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
PictureBox PictureBox1 = new PictureBox();
PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
// Add the new control to its parent's controls collection
this.Controls.Add(PictureBox1);
}
catch (Exception ex)
{
MessageBox.Show("Error loading image" + ex.Message);
}
}
}
The problem is that my image is shown at the top left corner of my form, when I have left almost quarter of my down-right side for this purpose. 问题是我的图像显示在我的表单的左上角,当我为此目的离开了几乎四分之一的右下角时。 How can I show it there?
我怎么能在那里展示它?
Like I said in my comment, here's how: How to: Position Controls on Windows Forms . 就像我在评论中所说,这是如何: 如何:在Windows窗体上定位控件 。
PictureBox PictureBox1 = new PictureBox();
PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
PictureBox1.Location = new Point(20, 100); //20 from left and 100 from top
this.Controls.Add(PictureBox1);
Or change it afterwards: 或者之后改变它:
PictureBox1.Top += 50; //increase distance from top with 50
您可以在将PictureBox添加到Parent之前设置它的location属性。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.