如何在Matplotlib的3D散点图中关闭透明度？

Question

I'm using Matplotlib's Axes3D to create a scatter plot with custom colors like this:

from mpl_toolkits.mplot3d import Axes3D
from matplotlib import pyplot as plt

fig = plt.figure(1)
ax = Axes3D(fig)
ax.scatter(xval, yval, zval, c=cval, cmap=plt.cm.gray)

This works fine, but matplotlib automatically adds some shading to make more distant points appear more transparent/in a lighter color than closer points. This makes it very hard to visually compare the colors of the individual points.

Is there some way to turn this off?

Answer 1

This is actually a feature of Matplotlib's 2d plot scatter plot as well, and here is a question with a potential solution to it.

Scatter 's inputs are what actually needs to be configured.

Answer 2

只需在散点函数中添加alpha = 1作为参数。

ax.scatter(xval, yval, zval, c=cval, alpha = 1, cmap=plt.cm.gray)

Answer 3

You need to add depthshade=False as an argument in the scatter function.

ax.scatter(xval, yval, zval, c=cval, cmap=plt.cm.gray, depthshade=False)

Matplotlib 3D tutorial