Calculate difference between values in consecutive rows by group

Question

This is a my df (data.frame):

group value
1     10
1     20
1     25
2     5
2     10
2     15 

I need to calculate difference between values in consecutive rows by group.

So, I need a that result.

group value diff
1     10    NA # because there is a no previous value
1     20    10 # value[2] - value[1]
1     25    5  # value[3] value[2]
2     5     NA # because group is changed
2     10    5  # value[5] - value[4]
2     15    5  # value[6] - value[5]

Although, I can handle this problem by using ddply , but it takes too much time. This is because I have a lot of groups in my df . (over 1,000,000 groups in my df )

Are there any other effective approaches to handle this problem?

Answer 1

The package data.table can do this fairly quickly, using the shift function.

require(data.table)
df <- data.table(group = rep(c(1, 2), each = 3), value = c(10,20,25,5,10,15))
#setDT(df) #if df is already a data frame

df[ , diff := value - shift(value), by = group]    
#   group value diff
#1:     1    10   NA
#2:     1    20   10
#3:     1    25    5
#4:     2     5   NA
#5:     2    10    5
#6:     2    15    5
setDF(df) #if you want to convert back to old data.frame syntax

---

Or using the lag function in dplyr

df %>%
    group_by(group) %>%
    mutate(Diff = value - lag(value))
#   group value  Diff
#   <int> <int> <int>
# 1     1    10    NA
# 2     1    20    10
# 3     1    25     5
# 4     2     5    NA
# 5     2    10     5
# 6     2    15     5

---

For alternatives pre- data.table::shift and pre- dplyr::lag , see edits.

Answer 2

You can use the base function ave() for this

df <- data.frame(group=rep(c(1,2),each=3),value=c(10,20,25,5,10,15))
df$diff <- ave(df$value, factor(df$group), FUN=function(x) c(NA,diff(x)))

which returns

  group value diff
1     1    10   NA
2     1    20   10
3     1    25    5
4     2     5   NA
5     2    10    5
6     2    15    5

Answer 3

用 tapply 试试这个

df$diff<-as.vector(unlist(tapply(df$value,df$group,FUN=function(x){ return (c(NA,diff(x)))})))

Answer 4

Since dplyr 1.1.0 , you can shorten the dplyr version with inline temporary grouping with .by :

mutate(df, diff = value - lag(value), .by = group)