I am working with WPF and I have an application that the user loads an image file into a RichTextBox
and they can rotate the image and print it. I am not sure as to why the image after it has been rotated will not print as it is displayed on the screen. Instead it prints the original. I am new to this so any help would be greatly appreciated!
The following is the code for my application. Code when the retrieve file Button
is clicked:
private void retrieve_button_Click(object sender, RoutedEventArgs e)
{
//Retrieve the file or image you are looking for
OpenFileDialog of = new OpenFileDialog();
of.Filter = "Formats|*.jpg;*.png;*.bmp;*.gif;*.ico;*.txt|JPG Image|*.jpg|BMP image|*.bmp|PNG image|*.png|GIF Image|*.gif|Icon|*.ico|Text File|*.txt";
var dialogResult = of.ShowDialog();
if (dialogResult == System.Windows.Forms.DialogResult.OK)
{
try
{
System.Windows.Controls.RichTextBox myRTB = new System.Windows.Controls.RichTextBox();
{
Run myRun = new Run();
System.Windows.Controls.Image MyImage = new System.Windows.Controls.Image();
MyImage.Source = new BitmapImage(new Uri(of.FileName, UriKind.RelativeOrAbsolute));
InlineUIContainer MyUI = new InlineUIContainer();
MyUI.Child = MyImage;
rotateright_button.IsEnabled = true;
print_button.IsEnabled = true;
Paragraph paragraph = new Paragraph();
paragraph.Inlines.Add(myRun);
paragraph.Inlines.Add(MyUI);
FlowDocument document = new FlowDocument(paragraph);
richTextBox.Document = document;
}
}
catch (ArgumentException)
{
System.Windows.Forms.MessageBox.Show("Invalid File");
}
}
}
When the rotate right button is clicked the following code is executed:
RotateTransform cwRotateTransform;
private void rotateright_button_Click(object sender, RoutedEventArgs e)
{
richTextBox.LayoutTransform = cwRotateTransform;
if (cwRotateTransform == null)
{
cwRotateTransform = new RotateTransform();
}
if (cwRotateTransform.Angle == 360)
{
cwRotateTransform.Angle = 0;
}
else
{
cwRotateTransform.Angle += 90;
}
}
After the Image
has been loaded and rotated the user can use the following code to print:
private void InvokePrint(object sender, RoutedEventArgs e)
{
System.Windows.Controls.PrintDialog printDialog = new System.Windows.Controls.PrintDialog();
if ((bool)printDialog.ShowDialog().GetValueOrDefault())
{
FlowDocument flowDocument = new FlowDocument();
flowDocument = richTextBox.Document;
flowDocument.ColumnWidth = printDialog.PrintableAreaWidth;
flowDocument.PagePadding = new Thickness(65);
IDocumentPaginatorSource iDocPag = flowDocument;
printDialog.PrintDocument(iDocPag.DocumentPaginator, "Print Document");
}
}
Try this (substitute yourImageControl in the first line, specify which RotateFlipType you want and be sure to reference the System.Drawing dll):
System.Drawing.Bitmap bitmap = BitmapSourceToBitmap((BitmapSource)YourImageControl.Source);
bitmap.RotateFlip(System.Drawing.RotateFlipType.Rotate90FlipNone);
public static System.Drawing.Bitmap BitmapSourceToBitmap(BitmapSource bitmapsource)
{
System.Drawing.Bitmap bitmap;
using (MemoryStream outStream = new MemoryStream())
{
BitmapEncoder enc = new BmpBitmapEncoder();
enc.Frames.Add(BitmapFrame.Create(bitmapsource));
enc.Save(outStream);
bitmap = new System.Drawing.Bitmap(outStream);
}
return bitmap;
}
Another option for conversion...
PS You would get a better answer in less time if you posted some code and told us more about what you have tried .
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