Show/hide image with JavaScript
Question
I have an HTML page with an image that I set to be invisible by CSS visibility: hidden . I want to make a link called "Show image", so that when I click on it, the image appears.
Now, I don't know how to make such a link, since normally a link with <a href=...> links to some other page. In my case, I want the link to invoke a JavaScript to display the image.
6 answers
solution1
44 ACCPTED 2013-03-10 02:54:06
If you already have a JavaScript function called showImage defined to show the image, you can link as such:
<a href="javascript:showImage()">show image</a>
If you need help defining the function, I would try:
function showImage() {
var img = document.getElementById('myImageId');
img.style.visibility = 'visible';
}
Or, better yet,
function setImageVisible(id, visible) {
var img = document.getElementById(id);
img.style.visibility = (visible ? 'visible' : 'hidden');
}
Then, your links would be:
<a href="javascript:setImageVisible('myImageId', true)">show image</a>
<a href="javascript:setImageVisible('myImageId', false)">hide image</a>
solution2
6 2013-03-10 02:56:03
It's pretty simple.
HTML:
<img id="theImage" src="yourImage.png">
<a id="showImage">Show image</a>
JavaScript:
document.getElementById("showImage").onclick = function() {
document.getElementById("theImage").style.visibility = "visible";
}
CSS:
#theImage { visibility: hidden; }
solution3
3 2013-03-10 02:58:31
You can do this with jquery just visit http://jquery.com/ to get the link then do something like this
<a id="show_image">Show Image</a>
<img id="my_images" style="display:none" src="http://myimages.com/img.png">
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('#show_image').on("click", function(){
$('#my_images').show('slow');
});
});
</script>
or if you would like the link to turn the image on and off do this
<a id="show_image">Show Image</a>
<img id="my_images" style="display:none;" src="http://myimages.com/img.png">
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('#show_image').on("click", function(){
$('#my_images').toggle();
});
});
</script>
solution4
2 2013-03-10 02:57:50
Here is a working example: http://jsfiddle.net/rVBzt/ (using jQuery)
<img id="tiger" src="https://twimg0-a.akamaihd.net/profile_images/2642324404/46d743534606515238a9a12cfb4b264a.jpeg">
<a id="toggle">click to toggle</a>
img {display: none;}
a {cursor: pointer; color: blue;}
$('#toggle').click(function() {
$('#tiger').toggle();
});
solution5
2 2015-04-27 05:55:34
This is working code:
<html>
<body bgcolor=cyan>
<img src ="backgr1.JPG" id="my" width="310" height="392" style="position: absolute; top:92px; left:375px; visibility:hidden"/>
<script type="text/javascript">
function tend() {
document.getElementById('my').style.visibility='visible';
}
function tn() {
document.getElementById('my').style.visibility='hidden';
}
</script>
<input type="button" onclick="tend()" value="back">
<input type="button" onclick="tn()" value="close">
</body>
</html>
solution6
0 2016-11-29 03:54:36
HTML
<img id="theImage" src="yourImage.png">
<a id="showImage">Show image</a>
JavaScript:
document.getElementById("showImage").onclick = function() {
document.getElementById("theImage").style.display = "block";
}
CSS:
#theImage { display:none; }
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