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Populating MySQL data with Google Charts

I'd like to create a pie chart which basically should display how many tasks a student has completed out of all tasks he has been assigned to. so my table for tasks looks like this

tasks task_id | task_student_id | task_status

*task_student_id* references the *user_id* in the students table

So lets say my sample data for student with user_id looks like this in the tasks table

task_id | task_student_id |task_status 1 6 complete 2 6 complete 3 6 not_complete 4 6 not_complete 5 6 complete

So the pie chart for this student should display either the number of completed and not completed tasks or the percentage (ie 40% not complete 60%complete)

I found a tutorial online. There's two php files the first one lets you select the user_id from students table

<html>
<head>
  <!--Load the AJAX API-->
  <script type="text/javascript" src="http://www.google.com/jsapi"></script>
  <script type="text/javascript" src="jquery-1.7.1.min.js"></script>
  <script type="text/javascript">

  // Load the Visualization API and the piechart,table package.
  google.load('visualization', '1', {'packages':['corechart','table']});

  function drawItems(num) {
    var jsonPieChartData = $.ajax({
      url: "getpiechartdata.php",
      data: "q="+num,
      dataType:"json",
      async: false
    }).responseText;

    var jsonTableData = $.ajax({
      url: "gettabledata.php",
      data: "q="+num,
      dataType:"json",
      async: false
    }).responseText;

    // Create our data table out of JSON data loaded from server.
    var piechartdata = new google.visualization.DataTable(jsonPieChartData);
    var tabledata = new google.visualization.DataTable(jsonTableData);

    // Instantiate and draw our pie chart, passing in some options.
    var chart = new google.visualization.PieChart(document.getElementById('chart_div'));
    chart.draw(piechartdata, {
      width: 700,
      height: 500,
      chartArea: { left:"5%",top:"5%",width:"90%",height:"90%" }
    });

    // Instantiate and draw our table, passing in some options.
    var table = new google.visualization.Table(document.getElementById('table_div'));
    table.draw(tabledata, {showRowNumber: true, alternatingRowStyle: true});
  }

  </script>
</head>
<body>
  <form>
  <select name="users" onchange="drawItems(this.value)">
  <option value="">Select a student:</option>
  <?php
    $dbuser="";
    $dbname="";
    $dbpass="";
    $dbserver="";
    // Make a MySQL Connection
    mysql_connect($dbserver, $dbuser, $dbpass) or die(mysql_error());
    mysql_select_db($dbname) or die(mysql_error());
    // Create a Query
    $sql_query = "SELECT user_id, user_name FROM students";
    // Execute query
    $result = mysql_query($sql_query) or die(mysql_error());
    while ($row = mysql_fetch_array($result)){
    echo '<option value='. $row['user_id'] . '>'. $row['user_name'] . '</option>';
    }
    mysql_close($con);
  ?>
  </select>
  </form>
  <div id="chart_div"></div>
  <div id="table_div"></div>
</body>
</html>

and then the second php file populates the chart based on the user_id selected

<?php
  $q=$_GET["q"];

  $dbuser="";
  $dbname="";
  $dbpass="";
  $dbserver="";

  $sql_query = "SELECT task_status, COUNT(*) FROM tasks
    WHERE  task_student_id=" . $q . ""

  $con = mysql_connect($dbserver,$dbuser,$dbpass);
  if (!$con){ die('Could not connect: ' . mysql_error()); }
  mysql_select_db($dbname, $con);

  $result = mysql_query($sql_query);

    $data = array('cols' => array(array('label' => 'Not completed', 'type' => 'string'),
                              array('label' => 'Completed', 'type' => 'string')),
              'rows' => array());

    while($row = mysql_fetch_row($result)) {
   $data['rows'][] = array('c' => array(array('v' => $row[0]), array('v' => $row[1])));
}    

echo json_encode($data);



  mysql_close($con);
?>

I'm sure I'm doing something wrong with the arrays and the query. Also I was thinking of creating two separate sql queries and to save them in two php variables; $not_completed, $completed and populate it in the chart. Don't know which one is the best option for my question. can someone please help?

have a look at https://developers.google.com/chart/ to find a documentation of google charts. if you already have both variables $complete and $not_complete you can use this example http://pastebin.com/qsB0hqmJ and you should improve your mysql/php code by using mysql_result.

$tasks_completed = mysql_result(mysql_query("SELECT COUNT(*) FROM tasks..."),0);

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