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Paypal API with PHP and cURL

I'm attempting "the first call" as outlined by the Paypal API documentation. This is the example provided that I'm following:

curl https://api.sandbox.paypal.com/v1/oauth2/token \
 -H "Accept: application/json" \
 -H "Accept-Language: en_US" \
 -u "EOJ2S-Z6OoN_le_KS1d75wsZ6y0SFdVsY9183IvxFyZp:EClusMEUk8e9ihI7ZdVLF5cZ6y0SFdVsY9183IvxFyZp" \
 -d "grant_type=client_credentials"

I have constructed a curl instance in PHP with all the above headers apart from the last one. What does a -d flag convert to as a curl option in PHP? There is little explanation there as far as I can tell. I managed to deduce -u as CURLOPT_USERPWD .

Having a good trawl around I pieced together parts from developers with other problems. I successfully gained my access token using the following code:

<?php

$ch = curl_init();
$clientId = "myId";
$secret = "mySecret";

curl_setopt($ch, CURLOPT_URL, "https://api.sandbox.paypal.com/v1/oauth2/token");
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_USERPWD, $clientId.":".$secret);
curl_setopt($ch, CURLOPT_POSTFIELDS, "grant_type=client_credentials");

$result = curl_exec($ch);

if(empty($result))die("Error: No response.");
else
{
    $json = json_decode($result);
    print_r($json->access_token);
}

curl_close($ch);

?>

@Lee point the right way but if u are using and old php version it wont work. But Lee version will not show up the error. Use these instead, i only add the error part to see what is going on.

$ch = curl_init();
$clientId = "";
$secret = "";

curl_setopt($ch, CURLOPT_URL, "https://api.sandbox.paypal.com/v1/oauth2/token");
curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_USERPWD, $clientId.":".$secret);
curl_setopt($ch, CURLOPT_POSTFIELDS, "grant_type=client_credentials");

$result = curl_exec($ch);
$err = curl_error($ch);

$access_token="";
if ($err) {
  echo "cURL Error #:" . $err;
}
else
{
    $json = json_decode($result);
   // print_r($json->access_token);
    $access_token = $json->access_token;
}

If u are having and old PHP version it is posible it wont work and it will show this error:

cURL Error #:error:14077410:SSL routines:SSL23_GET_SERVER_HELLO:sslv3 alert handshake failure

Just stack overflow it! Here they discuss the problem

JSON美国英语似乎是Defaults ,但要完全符合要求,请添加以下行:

curl_setopt($ch, CURLOPT_HTTPHEADER, "Accept: application/json, Accept-Language: en_US");

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