Hard to come up with a title, my apologizes.
Problem is this: Since modern web-browsers disable pop-up windows I am in need of a work-around.
When a visitor comes to the website they are prompt to press a button. Once the button is pressed a pop-up window is launched with the following code:
w = window.open('/audio/audioplayer.php?id='+audioId, 'audioplayer', params);
Now that the pop-up is open I would like when the visitor views other pages the pop-up is loaded with specific information based on whatever page they are on.
I am not sure if this is possible or how I can do this (check if the pop-up window is open, and if it is load the information, and if its not re-display the button)
I don't think it is possible to detect where the popup is open of not.
Have you thought about using a dialog? Rather than a popup?
window.open
returns a windowObjectReference - this is the only way you can talk to the popup window. In particular, you can tell if that window is closed with the windowObjectReference.closed
attribute. And the popup window has a window.opener
attribute that references the parent window back. You can use both to communicate.
However, it seems you want to keep this communication between page loads. You have a few options:
window.opener
. This link shows this approach and also another one with frames. position: fixed
could get you a similar result, and might save you from that method of communication between windows, however it also leads to having one dialog per page, so you need to ask the server if another instance of the dialog is running. Not quite sure if other methods of sync are viable for this (localstorage?)
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