Insert values from database into select option

Question

i want to put some fields from my database into select options. Therefore i made a function, nl showProjects. I want to show these options but my form isn't showing that values. I don't know where my mistake is...

public function showProjects() {
    $db = new Db();
    $select = "SELECT project_title FROM tblprojects ORDER BY project_title ASC";
    $result = $db -> conn -> query($select);
    $option ="";
    while ($row = mysql_fetch_assoc($result)) {
        $option .= '<option  value = "' . $row['project_title'] . '">' . $row['project_title'] . '</option>';
    }   
    return $option;     
}

I want to show it in this way:

<div class="control-group">
    <label class="control-label" for="Bug_Project">Project</label>
    <div class="controls">
        <select name="Bug_Project" class="span5" >
        <?php if(isset($bug)) $bug->showProjects(); ?>
        </select>
    </div>
</div>

Answer 1

除非您使用的是我从未见过的某种框架，否则您需要echo结果以使它们在页面上可见。

<?php if(isset($bug)) echo $bug->showProjects(); ?>