echo "No of days:";
$var1 = file_get_contents('path to file');
echo $var1;
$var2= "-".$var1." days"; // var2= -2 days
$today = date("M d, Y");
echo $today;
$NewDate=Date(strtotime($var2));
echo date('M d, Y', $NewDate);
Error:Warning: date() expects parameter 2 to be long,
尝试这个:
$var2= $var1." days ago";
$var = file_get_contents('path to file');
echo date('M d Y',strtotime("-$var days"));
Why not do it like this:
$date = new DateTime(date("M d, Y"));
$todayPlusTwoDays = $date->add(new DateInterval('P2D'));
If $var1 holds the amount of days to add, simply:
$todayPlusTwoDays = $date->add(new DateInterval('P'. $var1 .'D'));
From me
Remove this
$today = date("M d, Y");
echo $today;
You are not using it anyway.
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