How do I get the “ID” number from a mysql record and use it to update that record using php?
Question
Here is my test form (link to form removed) if you click on the update ticket link it will bring you to a page to add additional information to the record. I see the id for that record passed to the form in the browser url as the end of the url says ?id=10 or whatever the id number for that record is. This is where I'm stuck, I can't get the record to update, I input the info in the form and click the update button and it tells me it added 1 record but it doesn't add the info to MySQL and I don't get any errors either. so here is the code I'm using to update the record:
<?php
include 'db_connect.php';
$city=$_POST['city'];
$state=$_POST['state'];
$zip=$_POST['zip'];
$id=$_REQUEST['id'];
mysql_query("UPDATE `test` SET
`city` = '$city',
`state` = '$state',
`zip` = '$zip',
WHERE `id` = '$id'")
?>
I added a hidden input field to my form with the name of 'id' thinking that was what was wrong but no change. What am I doing wrong? what do I need to do to pass the id? Thanks!
Adding the code for my update form:
<html>
<body>
<form action="update.php" method="post">
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>">
City <input type="text" name="city">
State<input type="text" name="state">
Zip <input type="text" name="zip">
<input type="submit" value="update">
</form>
</body>
</html>
Revised update code:
<?php
include 'db_connect.php';
$city=$_POST['city'];
$state=$_POST['state'];
$zip=$_POST['zip'];
$id=$_POST['id'];
mysql_query("UPDATE `test` SET `city` = '$city', `state` = '$state', `zip` = '$zip' WHERE `id` = '$id'");
?>
2 answers
solution1
5 ACCPTED 2013-05-31 06:15:32
You need to post id with the form.
//Add this hidden field inside form to store and post id
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>"/>
The id gets lost when form is posted. so we need to store it and send it with the form.
// remove the comma before where in this line
mysql_query("UPDATE `test` SET `city` = '$city', `state` = '$state', `zip` = '$zip' WHERE `id` = '$id'");
solution2
3 2013-05-31 06:20:49
You are passing id by GET method. so use $_GET['id] to get id. Assign this id to a hidden field. Like: <input type="hidden" name="id" value="<?php echo $_GET['id']; ?>"/>
In update page. $id=$_POST['id'];//get id value by post method
mysql_query("UPDATE `test` SET `city` = '$city', `state` = '$state', `zip` = '$zip', WHERE `id` = '$id'");
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