I have id variable and date variable where there are multiple dates for a given id (a panel). I would like to generate a new variable based on whether ANY of the years for a given id meet a logical condition. I am not sure of how to code it so please don't take the following as R code, just as logical pseudocode. Something like
foreach(i in min(id):max(id)) {
if(var1[yearvar[1:max(yearvar)]=="A") then { newvar==1}
}
As an example:
ID Year Letter
1 1999 A
1 2000 B
2 2000 C
3 1999 A
Should return newvar
1 1 0 1
Since data[ID==1]
contains A in some year, it should also ==1
in 2000 despite Letter==B
that year.
Here's a solution using plyr
:
library(plyr)
a <- ddply(dat, .(ID), summarise, newvar = as.numeric(any(Letter == "A")))
merge(ID, a, by="ID")
Here's a way of approaching it with base R:
#Find which ID meet first criteria
withA <- unique(dat$ID[dat$Letter == "A"])
#add new column based on whether ID is in withA
dat$newvar <- as.numeric(dat$ID %in% withA)
# ID Year Letter newvar
# 1 1 1999 A 1
# 2 1 2000 B 1
# 3 2 2000 C 0
# 4 3 1999 A 1
Without using a package:
dat <- data.frame(
ID = c(1,1,2,3),
Year = c(1999,2000,2000,1999),
Letter = c("A","B","C","A")
)
tableData <- table(dat[,c("ID","Letter")])
newvar <- ifelse(tableData[dat$ID,"A"]==1,1,0)
dat <- cbind(dat,newvar)
# ID Year Letter newvar
#1 1 1999 A 1
#2 1 2000 B 1
#3 2 2000 C 0
#4 3 1999 A 1
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