Increase days to php current Date()

Question

How do I add a certain number of days to the current date in PHP?

I already got the current date with:

$today = date('y:m:d');

Just need to add x number of days to it

Answer 1

php supports c style date functions. You can add or substract date-periods with English-language style phrases via the strtotime function. examples...

$Today=date('y:m:d');

// add 3 days to date
$NewDate=Date('y:m:d', strtotime('+3 days'));

// subtract 3 days from date
$NewDate=Date('y:m:d', strtotime('-3 days'));

// PHP returns last sunday's date
$NewDate=Date('y:m:d', strtotime('Last Sunday'));

// One week from last sunday
$NewDate=Date('y:m:d', strtotime('+7 days Last Sunday'));

or

<select id="date_list" class="form-control" style="width:100%;">
<?php
$max_dates = 15;
$countDates = 0;
while ($countDates < $max_dates) {
    $NewDate=Date('F d, Y', strtotime("+".$countDates." days"));
    echo "<option>" . $NewDate . "</option>";
    $countDates += 1;
}
?>

Answer 2

一天是86400秒。

$tomorrow = date('y:m:d', time() + 86400);

Answer 3

The simplest way to add x no. of days..

echo date('Y-m-d',strtotime('+1 day'));    //+1 day from today

OR from specified date...

echo date('Y-m-d',strtotime('+1 day', strtotime('2007-02-28')));

Answer 4

With php 5.3

    $date = new DateTime();
    $interval = new DateInterval('P1D');
    echo $date->format('Y-m-d') , PHP_EOL;
    $date->add($interval);
    echo $date->format('Y-m-d'), PHP_EOL;
    $date->add($interval);
    echo $date->format('Y-m-d'), PHP_EOL;

will output

2012-12-24

2012-12-25

2012-12-26

Answer 5

The date_add() function should do what you want. In addition, check out the docs (unofficial, but the official ones are a bit sparse) for the DateTime object, it's much nicer to work with than the procedural functions in PHP.

Answer 6

If you need this code in several places then I'd suggest that you add a short function to keep your code simpler and easier to test.

function add_days( $days, $from_date = null ) {
    if ( is_numeric( $from_date ) ) { 
        $new_date = $from_date; 
    } else { 
        $new_date = time();
    }

    // Timestamp is the number of seconds since an event in the past
    // To increate the value by one day we have to add 86400 seconds to the value
    // 86400 = 24h * 60m * 60s
    $new_date += $days * 86400;

    return $new_date;
}

Then you can use it anywhere like this:

$today       = add_days( 0 );
$tomorrow    = add_days( 1 );
$yesterday   = add_days( -1 );
$in_36_hours = add_days( 1.5 );

$first_reminder  = add_days( 10 );
$second_reminder = add_days( 5, $first_reminder );
$last_reminder   = add_days( 3, $second_reminder );

Answer 7

$NewDate=Date('Y-m-d', strtotime('+365 days'));

echo $NewDate; //2020-05-21

Answer 8

Add 15 day to a select element (using "Alive to Die" suggestion)

<select id="date_list" class="form-control" style="width:100%;">
<?php
$max_dates = 15;
$countDates = 0;
while ($countDates < $max_dates) {
    $NewDate=Date('F d, Y', strtotime("+".$countDates." days"));
    echo "<option>" . $NewDate . "</option>";
    $countDates += 1;
}
?>

Answer 9

$NewTime = mktime(date('G'), date('i'), date('s'), date('n'), date('j') + $DaysToAdd, date('Y'));

From mktime documentation :

mktime() is useful for doing date arithmetic and validation, as it will automatically calculate the correct value for out-of-range input.

The advantage of this method is that you can add or subtract any time interval (hours, minutes, seconds, days, months, or years) in an easy to read line of code.

Beware there is a tradeoff in performance, as this code is about 2.5x slower than strtotime("+1 day") due to all the calls to the date() function. Consider re-using those values if you are in a loop.

Answer 10

You can also use Object Oriented Programming (OOP) instead of procedural programming:

$fiveDays = new DateInterval('P5D');
$today = new DateTime();
$fiveDaysAgo = $today->sub(fiveDays); // or ->add(fiveDays); to add 5 days

Or with just one line of code:

$fiveDaysAgo = (new DateTime())->sub(new DateInterval('P5D'));

Answer 11

<?php
$dt = new DateTime;
if(isset($_GET['year']) && isset($_GET['week'])) {
    $dt->setISODate($_GET['year'], $_GET['week']);
} else {
    $dt->setISODate($dt->format('o'), $dt->format('W'));
}
$year = $dt->format('o');
$week = $dt->format('W');
?>

<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week-1).'&year='.$year; ?>">Pre Week</a> 
<a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week+1).'&year='.$year; ?>">Next Week</a>
<table width="100%" style="height: 75px; border: 1px solid #00A2FF;">
<tr>
<td style="display: table-cell;
    vertical-align: middle;
    cursor: pointer;
    width: 75px;
    height: 75px;
    border: 4px solid #00A2FF;
    border-radius: 50%;">Employee</td>
<?php
do {
    echo "<td>" . $dt->format('M') . "<br>" . $dt->format('d M Y') . "</td>\n";
    $dt->modify('+1 day');
} while ($week == $dt->format('W'));
?>
</tr>
</table>