here is my ajax
var $this = $(this);
$.ajax({
url: "process.php",
dataType: 'json' ,
data :{
method:'POST',
id :id ,
img_val : img_val},
type : 'POST',
success: function(output_data){
if (output_data.msg == 'taken'){
---> $this.val('Saved !').delay(3000).val('Save') ;
} }
});
actually this code marked with --->
didnt work with delay it displays directly Save
if i remove delay(3000).val('Save')
it display Saved !
and what i want is display Saved !
and then wait 3 seconds and then display Save
. how can i achieve this ? thnaks
$this
is button .
[updated] use setTimeout(function(){ /* your code */},3000);
update : if you still want to use the jquery delay write it like this:
$('#dd').val('firstVal').delay(2000).queue(function(){$(this).val('SecondVal');}).delay(...;
and that's because the default queue of 'delay()' is 'fx' which doesn't include val() in it automatically, so you just have to add it to it.
var $this = $(this);
$.ajax({
url: "process.php",
dataType: 'json',
data: {
method:'POST',
id :id,
img_val : img_val
},
type: 'POST',
success: function(output_data) {
if (output_data.msg == 'taken') {
$this.val('Saved!');
setTimeout(function() { $this.val('Save'); }, 3000);
}
}
});
Using setTimeout( function , time ) is the best solution.
But if you want to animate the button, you can make it with jQuery .animate()
var $this = $(this);
$this.val("Saved!").animate(
{ opacity: 0.99 }, //transition
2000, //duration
function() { //animation complete
$this.val("Save");
});
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