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remove character columns from a numeric data frame

I have a data frame like the one you see here.

     DRSi       TP        DOC        DN          date     Turbidity   Anions 
     158        5.9       3371       264        14/8/06      5.83    2246.02
     217        4.7       2060       428        16/8/06      6.04    1632.29
     181        10.6      1828       219        16/8/06      6.11    1005.00
     397        5.3       1027       439        16/8/06      5.74    314.19
     2204       81.2      11770      1827       15/8/06      9.64    2635.39
     307        2.9       1954       589        15/8/06      6.12    2762.02
     136        7.1       2712       157        14/8/06      5.83    2049.86
     1502       15.3      4123       959        15/8/06      6.48    2648.12
     1113       1.5       819        195        17/8/06      5.83    804.42
     329        4.1       2264       434        16/8/06      6.19    2214.89
     193        3.5       5691       251        17/8/06      5.64    1299.25
     1152       3.5       2865       1075       15/8/06      5.66    2573.78
     357        4.1       5664       509        16/8/06      6.06    1982.08
     513        7.1       2485       586        15/8/06      6.24    2608.35
     1645       6.5       4878       208        17/8/06      5.96    969.32

Before I got here i used the following code to remove those columns that had no values at all or some NA's.

    rem = NULL
    for(col.nr in 1:dim(E.3)[2]){
      if(sum(is.na(E.3[, col.nr]) > 0 | all(is.na(E.3[,col.nr])))){
        rem = c(rem, col.nr)
      }
    }
    E.4 <- E.3[, -rem]  

Now I need to remove the "date" column but not based on its column name, rather based on the fact that it's a character string.

I've seen here ( Remove an entire column from a data.frame in R ) already how to simply set it to NULL and other options but I want to use a different argument.

First use is.character to find all columns with class character . However, make sure that your date is really a character , not a Date or a factor . Otherwise use is.Date or is.factor instead of is.character .

Then just subset the columns that are not characters in the data.frame, eg

df[, !sapply(df, is.character)]

I was having a similar problem but the answer above isn't resolve it for a Date columns (that's what I needed), so I've found another solution:

df[,-grep ("Date|factor|character", sapply (df, class))]

Will return you your df without Date, character and factor columns.

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