How to open IP Camera Url by OpenCV and python?

Question

I have install opencv on MacX(Lion) with ffmpeg support

import cv2
import cv
import base64
import time
import urllib2
import numpy as np

from cv2 import __version__

print(__version__)
video="http://xxx.223.91.91/mjpg/1/video.mjpg?dummy=param.avi"
vv = cv.CaptureFromFile(video)
cv2.namedWindow("preview")
vc = cv2.VideoCapture("http://xxx.223.91.91/mjpg/1/video.mjpg?dummy=param.mjpg")

but Show WARNING

2.4.2

WARNING: Couldn't read movie file http://xxx.223.91.91/mjpg/1/video.mjpg?dummy=param.avi

WARNING: Couldn't read movie file http://xxx.223.91.91/mjpg/1/video.mjpg?dummy=param.mjpg

I Google a lot of code, but could not find a solution to the problem. Please help me, thank you.

Answer 1

import cv2
import urllib 
import numpy as np

stream=urllib.urlopen('http://localhost:8080/frame.mjpg')
bytes=''
while True:
    bytes+=stream.read(16384)
    a = bytes.find('\xff\xd8')
    b = bytes.find('\xff\xd9')
    if a!=-1 and b!=-1:
        jpg = bytes[a:b+2]
        bytes= bytes[b+2:]
        i = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8),cv2.CV_LOAD_IMAGE_COLOR)
        cv2.imshow('i',i)
        if cv2.waitKey(1) ==27:
            exit(0)