php - function echo a variable

Question

I am currently writing some functions for a script I am working on. My problem is, that the way the content is generated is by a php variable.

So, to generate page contents, it must be like this:

$contents .="page content inside this";

If I make an echo like this:

echo "page content inside this";

then the echoed text will appear on top of the page. Therefore, I must use the $contents.=""; in order to generate page content.

I am currently writing a function which can quickly generate checkboxes. My function looks like this:

function checkbox($name, $value, $checked){

    if($checked == 1){
        $checked = "checked"; 
    }else{ 
        $checked ="";
    }

    $contents.="<div class='roundedOne'>
   <input type='checkbox' value='$value' id='roundedOne' name='$name' $checked />
   <label for='roundedOne'></label>
  </div>";

}

When I call the function inside a page, nothing appears:

$contents.="
".checkbox("name","value","1")."
";

I can imagine that the reason nothing happens when I call the function, is that I've used $contents instead of echo , but unfortunately that is my only option, as the script is encrypted, so I cannot change the way $contents behave.

My question is, how can I make the function print with $contents?

Answer 1

You need to declare $contents as global before using it inside the function (not recommended) -

global $contents;
$contents.="<div class='roundedOne'>
     <input type='checkbox' value='$value' id='roundedOne' 
     name='$name' $checked />
     <label for='roundedOne'></label>
     </div>";

Or, better yet, you can generate the content from your function and then return it -

function checkbox($name, $value, $checked){

    if($checked == 1){
        $checked = "checked"; 
    }else{ 
        $checked ="";
    }

    return "<div class='roundedOne'>
       <input type='checkbox' value='$value' id='roundedOne' name='$name' 
       $checked />
       <label for='roundedOne'></label>
       </div>";        
}

$contents.= checkbox("name","value","1");

Also, you are changing the type of your $checked parameter inside the function. This style of coding is strongly discouraged. Try not to change the type of variable in this manner, it will save you from a lot of trouble.

Answer 2

使用global $contents或在函数末尾return $contents

Answer 3

What have you returned from the function. Return the string from the function . or use $content as global variable as oliverbj suggested

Answer 4

Not sure if I understand your issue correctly. Have you try using global ?

<?php

$contents = "string string string";

function checkbox($name, $value, $checked){

    global $contents;

    if($checked == 1){
        $checked = "checked"; 
    }else{ 
        $checked ="";
    }

    $contents.="<div class='roundedOne'>
   <input type='checkbox' value='$value' id='roundedOne' name='$name' $checked />
   <label for='roundedOne'></label>
  </div>";

}

$contents.=" ".checkbox("name","value","1")." ";

echo $contents;

?>

Answer 5

Return value of $contents from function.

Using that way you can get value of $contents inside your page.

like,

function checkbox($name, $value, $checked){

    if($checked == 1){
        $checked = "checked"; 
    }else{ 
        $checked ="";
    }

    $contents.="<div class='roundedOne'>
   <input type='checkbox' value='$value' id='roundedOne' name='$name' $checked />
   <label for='roundedOne'></label>
  </div>";
  return $contents;
}

Answer 6

You are no returning value from your function.

So you didn't get anything as a response from checkbox function.

Just needs to return $contents from function and then echo that result will do for you.

function checkbox($name, $value, $checked){

    if($checked == 1){
        $checked = "checked"; 
    }else{ 
        $checked ="";
    }

    $contents.="<div class='roundedOne'>
   <input type='checkbox' value='$value' id='roundedOne' name='$name' $checked />
   <label for='roundedOne'></label>
  </div>";
  return $contents;
}

Then,

echo $contents;