So I have a view set up as such:
class toi(FlaskView):
def index(self):
...
return render_template('home.html')
@route('/api/')
@route('/api/<int:urlgid>/')
@route('/api/<int:urlgid>/<int:urlper>/')
def APIInstruction(self, urlgid=None, urlper=None):
return render_template('toi-instructions.html')
And then in my main app.py I have
from views.toi import toi
toi.register(app)
And then in the HTML that toi:index is ouputting I have
... <a href="{{ url_for('toi:APIInstruction') }}">how to use the API</a> ...
This gives me a BuildError (no further details) and I've been pulling my hair out trying to figure this out. If I remove the @routes the error goes away. If I get rid of the 2nd and 3rd @routes it does not give me a builderror. If I put the urlgid and urlper in the url_for() function it does not change anything. I've tried changing the endpoints, I've tried changing url_for to toi:api.
I am not sure what is wrong to cause this BuildError.
When you use multiple routes for a single view, what happens is multiple endpoints get created (one for each route). In order to help you distinguish between each endpoint, Flask-Classy will append an index to the end of the expected route name. The order is from 0 to n starting from the last route defined. So given your example:
@route('/api/') # use: "toi:APIInstruction_2"
@route('/api/<int:urlgid>/') # use: "toi:APIInstruction_1"
@route('/api/<int:urlgid>/<int:urlper>/') # use: "toi:APIInstruction_0"
def APIInstruction(self, urlgid=None, urlper=None):
return render_template('toi-instructions.html')
You can read more about this behavior here: http://pythonhosted.org/Flask-Classy/#using-multiple-routes-for-a-single-view
Alternatively (this is the method I prefer) you can specify the endpoint you want to use explicitly in any @route
decorator. For example:
@route('/api/', endpoint='apibase')
Will be accessible using:
url_for('apibase')
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