I have a view controller that has a button on it. The button is the Privacy Policy. When it's clicked it goes to the proper IBAction and I create the privacy controller.
- IBAction ...
{
PrivacyPolicyViewController *privacy = [[PrivacyPolicyViewController alloc] init];
.....
}
I want to create a modal view of the privacy controller that has a UIWebView that animates itself upward and a back button to close it in ios 7. The ways I see online all are ios 6 and seem deprecated.
Use something like this:
// assuming your controller has identifier "privacy" in the Storyboard
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Main" bundle:nil];
PrivacyPolicyViewController *privacy = (PrivacyPolicyViewController*)[storyboard instantiateViewControllerWithIdentifier:@"privacy"];
// present
[self presentViewController:privacy animated:YES completion:nil];
// dismiss
[self dismissViewControllerAnimated:YES completion:nil];
[self presentmodalviewcontroller:vc];
has been deprecated .
you can try for
[self presentViewController:viewController animated:YES completion:nil];
it will work for you..
If you are using Storyboards, you can use a segue to present a modal view controller as well, and do it programmatically.
[self performSegueWithIdentifier:@"toNewView" sender:self];
It's a nice clean way to do it because you don't have to import a .h file to instantiate the second controller object for the presentViewController
method.
To dismiss it, you just use an unwind segue .
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Main" bundle:nil];
taskQueeDetails *privacy = (taskQueeDetails*)[storyboard instantiateViewControllerWithIdentifier:@"taskQueeDetails"];
// Present the modal
[self presentViewController:privacy animated:YES completion:nil];
use the code and change the string instantiateViewControllerWithIdentifier:@"taskQueeDetails"]; it will work fine
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