I used the code from this answer to split my train data into two sets.
trainLabels <- read.csv(trainLabels.file, stringsAsFactors=F, header=FALSE)
> str(trainLabels)
'data.frame': 1000 obs. of 1 variable:
$ V1: int 1 0 0 1 0 1 0 1 1 0 ...
trainLabelsTrain <- trainLabels[train_ind, ]
trainLabelsTest <- trainLabels[-train_ind, ]
> str(trainLabelsTrain)
int [1:750] 0 1 0 0 0 0 1 1 1 0 ...
Then I would like to have a data.frame just like the original data ( trainLabels
).
How can I get a data.frame?
use the drop = FALSE
command in your subsetting...
# drop = TRUE by default in `[` subsetting...
df <- data.frame( a = 1:10 )
df[ c(1,3,5) , ]
#[1] 1 3 5
# With drop = FALSE...
df[ c(1,3,5) , , drop = FALSE ]
# a
#1 1
#3 3
#5 5
When drop = TRUE
R will attempt to coerce the result to the lowest possible dimension, in this case an atomic vector, as there is only a single column.
Obviously I like @SimonO101's answer, but I just thought I'd add that one could also use the split
function here:
df <- data.frame(a = 1:10)
set.seed(1)
x <- rbinom(10,1,.5)
out <- split(df,x)
The result would be a list of two dataframes:
> str(out)
List of 2
$ 0:'data.frame': 4 obs. of 1 variable:
..$ a: int [1:4] 1 2 5 10
$ 1:'data.frame': 6 obs. of 1 variable:
..$ a: int [1:6] 3 4 6 7 8 9
This is because drop=TRUE
is the default in [
but drop=FALSE
is the default in split
.
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