I'm trying to emulate an angled path line similar to this image .
The way I'm doing it is using two trapezoid shapes, and overlapping one with another that would be the same as the background as seen in this jsFiddle .
But I realized I want the rest of the shape to be transparent instead of being able to overlap other objects.
The core is just a little bit of CSS, an outlineMaker div inside of a rightTrapezoid div.
.rightTrapezoid {
border-bottom: 100px solid red;
border-left: 0 solid transparent;
border-right: 50px solid transparent;
height: 0;
width: 100px;
}
.outlineMaker {
border-bottom: 80px solid white;
border-left: 0 solid transparent;
border-right: 40px solid transparent;
height: 20px;
width: 80px;
}
Is there a neat and concise way to do this?
Complete example following nice using @Feng Huo tip.
HTML Markup
<div class="trapezoidLine1">
<div class="trapezoidLine2"/>
</div>
<div class="trapezoidLine3">
<div class="trapezoidLine4"/>
</div>
CSS
.trapezoidLine1 {
position: absolute;
width: 200px;
height: 2px;
background: blue;
}
.trapezoidLine3 {
position: relative;
margin-top:45px;
width: 207px;
height: 2px;
background:blue;
}
.trapezoidLine2 {
position: absolute;
width: 47px;
height: 2px;
background: blue;
left: 200px;
-webkit-transform-origin: 0% 0%;
-webkit-transform: rotateZ(80deg);
}
.trapezoidLine4 {
position: absolute;
width: 45px;
height: 2px;
background: blue;
-webkit-transform-origin: 0% 0%;
-webkit-transform: rotateZ(270deg);
}
Try the fiddle
Instead of trying to force this way to work with a twist somehow. I gave it a couple minutes of thought and realized DUHHHHHHH, I can just do this :
<div class="trapezoidLine1">
<div class="trapezoidLine2"/>
</div>
.trapezoidLine1 {
position: absolute;
width: 200px;
height: 10px;
background: blue;
}
.trapezoidLine2 {
position: absolute;
width: 200px;
height: 10px;
background: blue;
left: 200px;
-webkit-transform-origin: 0% 0%;
-webkit-transform: rotateZ(45deg);
}
Herp a derp...
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